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3 years ago

11

Joe spends $1.75 every time he buys a snack with his lunch. He has $16.25 to spend. Write an inequality showing how many times (

x) that Joe can buy a snack with his lunch.

1 answer:

Alex787 [66]3 years ago

6 0

Answer:

16.25=1.75x

Step-by-step explanation:

so write it like this to that the bigger number(16.25) is on the left then write the other number(1.75)then put the X by the 1.75

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In a certain constituency, there are 8 500 voters and

babymother [125]

First let's find how much is 15% of 8500 voters.

To do that, we can multiply 15 by 8500 and then divide by 100.

Work: 15 x 8500 = 127500

127500/100 = 1275

Therefore 15 percent of 8500 is 1275.

Then, we subtract 1275 from 8500 to find the amount of people who did vote.

8500 - 1275 = 7,225

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The football team has a total of 50 jerseys. There are 10 medium-sized jerseys. What percent of the jerseys are medium-sized j

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Step-by-step explanation:

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Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

<u>x = 2</u>
<u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

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