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insens350 [35]
4 years ago
5

PLS HELP ILL GIVE BRAINLIEST <3 HELP ASAPPPPP

Mathematics
1 answer:
Alex_Xolod [135]4 years ago
4 0

Answer:

-3/2

Step-by-step explanation:

The slope goes down 3 and over 2.

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The distance from the top of the cone to the edge is 15 feet. The height of the cone is 6 feet. What is the radius of the cone?
soldi70 [24.7K]

Answer:

The radius of the cone is approximately 13.4 feet

Step-by-step explanation:

The dimensions of the given cone are;

The distance from the top of the cone to the edge of the cone = 15 feet

The height of the cone = 6 feet

The radius of the cone is given by the base of the right triangle formed by the slant length, the base radius and the height which is found using Pythagoras theorem as follows;

The radius of the cone, r = √((Slant distance)² + (Height)²)

∴ r = √((12 ft.)² + (6 ft.)²) ≈ 13.4 ft. (by rounding to the nearest 10th)

8 0
3 years ago
Solve each system of equations without graphing: 6t-9u=10 and 2t+3u=4
stepladder [879]

Answer:

6t-9u=10

2t+3u=4

t=11/6

u=1/9

Hope This Helps!!!

6 0
3 years ago
!!20 points!!
madam [21]

Answer:

y = 1/7x + 22

Step-by-step explanation:

since the line is <u>parallel</u>, the <u>slope should be the same</u>.

so we need to find the y-intercept to put in into slope-intercept form.

what I do, is simply plug in the y and x points into the equation y=mx+b

y=mx+b <em>-formula used</em>

21 = 1/7(-7) + b <em>-plug in</em>

21 = -1 + b <em>-multiply 1/7 and -7</em>

22 = b <em>-simplify to get the y-intercept</em>

since we now know the y-intercept and the slope, we can plug them in to get our answer, which will be y = 1/7x + 22

8 0
4 years ago
Answer the following please :) please choose 1 answer.
prohojiy [21]

Answer:

70%

Step-by-step explanation:

3:7 would be 30:70

6 0
3 years ago
Read 2 more answers
Cindys grandmother is five times her age. Find each of their ages if the sum of their ages is 90
yan [13]

Answer:

cindy=15 grandmother=75

Step-by-step explanation:

90 divide 6 equal to 15

6 0
3 years ago
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