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Lisa [10]
3 years ago
13

X + 2 y is greater than or equal to negative 3

Mathematics
1 answer:
EastWind [94]3 years ago
7 0
X+2y\geq -3 that may be wrong
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Vector v is shown in the graph.
Elis [28]

Question 4

<h3>Answer: Choice D</h3>

Explanation:

If the initial point is the origin, the coordinates of the terminal point form the vector itself in component form. We go from (-8,6) to <-8,6>. The notation change is from ordered pair to vector format.

We have a right triangle with legs of 8 and 6 units. The pythagorean theorem will help us determine the hypotenuse is 10. Therefore, the vector length is 10 units and we would say ||v|| = 10. We have a 6-8-10 right triangle.

===========================================================

Question 5

<h3>Answer: Choice B</h3>

Explanation:

Vector v starts at (2,5) and ends at (-3,-2).

The x component of the vector is x2-x1 = -3-2 = -5 meaning we move 5 units to the left when going from the start point to the endpoint.

At the same time we move 7 units down because y2-y1 = -2-5 = -7 which is the y component of the vector.

The component form of vector v is

v = <-5, -7>

it says "move 5 units left, 7 units down".

Apply the pythagorean theorem to find the length of the vector.

a^2+b^2 = c^2

c = sqrt(a^2 + b^2)

||v|| = sqrt( (-5)^2 + (-7)^2 )

||v|| = 8.602 which is approximate.

Now let's use the arctangent function to find the angle

theta = arctan(b/a)

theta = arctan(-7/(-5))

theta = 54.462 which is also approximate.

There's a problem however. This angle is in Q1 but the vector <-5,-7> is in Q3. An easy fix is to add on 180 to rotate to the proper quadrant.

54.462+180 = 234.462

which is the proper approximate angle for theta.

6 0
2 years ago
A couple has a 400 acre farm that they want to leave to their future grandchildren. They decide to give each grandchild 12% of t
ruslelena [56]

Answer:

48

Step-by-step explanation:

5 0
2 years ago
Find the coordinates of the missing vertex of rectangle ABCD with A(−5, 4), B(2, 4), and C(2, 0).
svlad2 [7]

Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

2

=

r

2

mu

2

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

2

=

2

1

u

2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

6 0
2 years ago
Sales price is 67.50 sales tax is 5% how much is the total amount paid
Zinaida [17]
$70.88

x/67.5=5/100
cross multiply
100x=337.5
divide 100
x=3.375 or 3.38

67.50+3.38= 70.88
7 0
3 years ago
561 rounded to the nearest hundred
insens350 [35]
561 rounded to the nearest hundred is 600
4 0
3 years ago
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