Answer:
(23.97, 24.03)
Step-by-step explanation:
Given the data:
224.120 224.001 224.017 223.982 223.989 223.961 223.960 224.089 223.987 223.976 223.902 223.980 224.098 224.057 223.913 223.999
Confidence interval = m ± Zcritical(s/√n)
n = sample size = 16
Zcritical at 95% = 1.96
Using calculator :
Sample mean, m = 224.0019
Standard deviation, s = 0.0618
Lower bound : 24.0019 - 1.96(0.0618/√16) = 23.971618
Upper bound : 24.0019 + 1.96(0.0618/√16) = 24.032182
(23.97, 24.03)
Answer:
10 pair of soccer shorts.
Step-by-step explanation:
Let the unknown be x.
Translating the word problem into an algebraic equation, we have;
2/5 yard = 1 pair of short
4 yard = x pair of short
Cross-multiplying, we have;
2x/5 = 4
Multiplying both sides by 5, we have;
2x = 20
x = 20/2
x = 10 pair of soccer shorts.
The calculation uses the accumulated daily balance method (ADB).
We assume the statement is based on calendar month (rare!).
George owes $500 from beginning to end of June, so 30 days out of 30.
Interest accrued is 500*0.013*30/30=$6.50.
He also owes $2000 from June 12 to June 30, so 19 days inclusively.
Interest accrued is $2000*.013*(19/30)=16.47
Total interest at the end of the month=$6.50+$16.47=$22.97
