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mars1129 [50]
3 years ago
6

Write a fraction could multiply by the numver 2 and have a product greater than 2?

Mathematics
1 answer:
larisa86 [58]3 years ago
8 0
Any improper fraction would work for this case since they are all greater than 1. For instance 3/2 * 2 would be equal to 3 which is greater than 2. 
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3x-4=5<br><br> Solve the equation above
SVEN [57.7K]

Answer:

The answer is x = 3

Explanation step by step

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Given the function f(x) =-2x+3x^2-5, what is the right end behavior
Leto [7]
The right-end behaviour of all polynomials is always (i.e. whether highest power is odd or even) increasing when the leading coefficient (coefficient of the highest powered variable) is positive.
Otherwise, it is decreasing.

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Simplify 6f+5g-3f+3g
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Step-by-step explanation:

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Can someone help me with this question?
Nikitich [7]
D. 5 5/6

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4 0
3 years ago
What is the difference 2x-3/3x^2-x+2/6x
Paul [167]

Answer: D

Step-by-step explanation:

To find the difference, we want to make sure both denominators are equal.

\frac{(6x)(2x-3)}{(6x)(3x^2)} -\frac{(3x^2)(x+2)}{(3x^2)(6x)}

Now that the denominators are equal, we can distribute and multiply out.

\frac{12x^2-18x}{18x^3} -\frac{3x^3+6x^2}{18x^3}

With the fractions multiplied out, we can actually put it into one large fraction.

\frac{12x^2-18x-3x^3-6x^2}{18x^3}

Let's subtract the top expression.

\frac{-3x^3+6x^2-18x}{18x^3}

This may seem like our final answer, but we can actually factor out an 3x in the numerator and denominator.

\frac{(3x)(-x^2+2x-6)}{(3x)(6x^2)}

With the 3x factored out, they cancel out because 3x/3x=1.

Our final answer is:

\frac{-x^2+2x-6}{6x^2}

5 0
3 years ago
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