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3 years ago

DO IT AND YOU GET 50 POINTS BUT IF YOU DO BOTH PAGES YOU GET BRAINLEYIST AWNSER.

Mathematics

2 answers:

irina1246 [14]3 years ago

8 0

Answer:

Step-by-step explanation:

23.) True, then False

24.) Yards, then feet. For both.

25.) 7.8

26.) 8.3

27.) 14.5

2nd page:

1.) 1+p

2.) 3+j

3.) 12-t

4.)8+s

5.) 3xd

6.) 5-y

7.) 1/2 divide m

8.) 1/3 divide e

9.) 10 x e

HOPE THIS HELPS!!!!

jeyben [28]3 years ago

5 0

Answer:

23. a-T b-F

24. Words- *3* times the number of *feet*

Variable- Let *y* represent the number of *yards*

Model- (I can't do it)

Expression- The number of feet in*3* yards is given by the expression *3y*

25. 7.8

26. 8.3

27. 14.5

28. Yes. The communitive property tells us that we can switch any two numbers in a multiplication or addition problem

*I did that page like a month ago*

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What is the product of 1/2 x - 1/4 and 5x^2 - 2x + 6? Write your answer in standard form?

marta [7]

Answer:

for a. you will first solve 5x²-2x+6 with

x=-b ± ✓b²-4ac

----------------

then put the two answers you will get into a bracket then multiply it with 1/2x - 1\4

then write in form of dis :- A ×10^n

Step-by-step explanation:

b. the two products are not the same

3 0

2 years ago

The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

Let X = number of hours spent per week on household chores

So, assuming data follows normal distribution; X ~ N( $\mu=28,\sigma^{2}=7^{2}$ )

The z score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = mean hours = 28

$\sigma$ = standard deviation = 7 hours

n = sample of adults = 49

Let $\bar X$ = sample mean hours spent per week on household chores

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P( $\bar X$ > 26.75 hours)

P( $\bar X$ > 26.75 hours) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{26.75-28}{\frac{7}{\sqrt{49} } }$ ) = P(Z > -1.25) = P(Z < 1.25)