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Andrews [41]
3 years ago
15

A company that manufactures computers established that a new employee can assemble N(t) components per day after t days of train

ing, as given by the function N(t) = 50t/t+4, t greaterthanorequalto 0 How many components per day can a new employee assemble after 6 days of training? How many days are needed for an employee to be able to assemble 45 components per day? Find the appropriate end-behavior of the function. Discuss its implications in this context
Mathematics
1 answer:
kari74 [83]3 years ago
4 0

6 days to make 30 and 36 days to make 45

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Suppose instead of comparing independent measurements taken from two groups, you used a matched-pairs experiment and one treatme
lina2011 [118]

You should use a T distribution to find the critical T value based on the level of confidence. The confidence level is often given to you directly. If not, then look for the significance level alpha and compute C = 1-alpha to get the confidence level. For instance, alpha = 0.05 means C = 1-0.05 = 0.95 = 95% confidence

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After that, you'll need the standard deviation of the differences. I recommend using a calculator to quickly find this. A spreadsheet program is also handy as well. Let sd be the standard deviation of the differences

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3 0
3 years ago
8 divided by 2/7 = help me
Ad libitum [116K]
The answer is 28!
you factor the numerator and denominator and cancel the common factors! <3
6 0
3 years ago
Read 2 more answers
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