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IRINA_888 [86]
3 years ago
8

Are the numbers 4/7 and 10/17.5 a proportion? Same question for the following....

Mathematics
2 answers:
zhenek [66]3 years ago
8 0
Proportional:

4/7 and 10/17.5
2/3 and 9/12
18/8 and 9/4


NOT proportional:

3/8 and 6/141
7/5 and 27/50
Serjik [45]3 years ago
6 0

Answer:

previous answer is right -

Step-by-step explanation:

2/3 and 9/12 is not proportional

You might be interested in
Convert to an improper fraction. Type in your answer with the negative in the numerator. -8 3/4 =
Sergeu [11.5K]

Answer:

-32/4

Step-by-step explanation:

-8 times 4= -32 put -32 over 4

8 0
3 years ago
Adrian is a songwriter who collects royalties on his songs whenever they are played in a commercial or movie. Adrian will earn $
gayaneshka [121]

Answer:

Adrian's songs played on 9 commercials and 5 movies.

Step-by-step explanation:

Let x denotes number of commercials and y denotes number of movies.

Total number of commercials and movies = 14

So,

x+y=14\\x=14-y\,\,\,\,...(i)

Adrian will earn $40 every time one of his songs is played in a commercial and he will earn $130 every time one of his songs is played in a movie

Total amount earned = $1010

40x+130y=1010\,\,\,...(ii)

Put x=14-y in (ii)

40(14-y)+130y=1010\\560-40y+130y=1010\\90y=1010-560\\90y=450\\y=\frac{450}{90}=5

Put y=5 in x=14-y

x=14-5=9

Therefore, Adrian's songs played on 9 commercials and 5 movies.

7 0
3 years ago
Jill bought 3 boxes of ice pops. Each box contains 4 orange ice pops and some cherry ice pops. The number of cherry ice pops in
Leya [2.2K]

Answer: 9 cherry ice pops

Step-by-step explanation:

if you bought 3 boxes and there is four orange one in each pack the that is

12 and 36 divided by 4 is 9 so there is 9 cherry ice pops

6 0
3 years ago
Which shows the best estimate to use<br> to find 43 × 78?
Over [174]

Answer:

The best estimate for 43x78 is 40x80

Step-by-step explanation:

43 rounded to the nearest ten is 40.

78 rounded to the nearest ten is 80.  

The answer to 40x80 is 3200

4 0
3 years ago
Ignoring leap days, the days of the year can be numbered 1 to 365. Assume that birthdays are equally likely to fall on any day o
faust18 [17]

Answer:

Follows are the solution to the given question:

Step-by-step explanation:

They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.

S=365^n

This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.

P(x)=\frac{1}{365^{n}}

if x is between 1 and 365 as well as the occurrence is just all similarly possible

In point i:

That somebody mentions their birthday throughout the party

Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.

In point ii:

Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.

In point iii:

Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.

6 0
3 years ago
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