Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a 
b 
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:




Solving (b): Probability that none are defective.
The probability that a selection is not defective is:

For two selections, the probability that all are not defective is:




Answer:
15;9;-8
Step-by-step explanation:
1. 5/3x-3=2/3x+12
x=15 once you combine like terms
2. 5x+35-3x+12=7x+2
2x+47=7x+2
5x=45
x=9
3. 12x+20-3=9x-7
12x+17=9x-7
3x=-24
x=-8
Answer:
123,456.789
Step-by-step explanation:
The ten thousandth place is less than 5.
Answer:
the one on top= c= -12
the bottom one= f= -15
Step-by-step explanation:
96 divided by 3 is 32
Therefor, it is divisible by 3
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