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nexus9112 [7]
3 years ago
8

Write the equation of a line, in slope intercept form, that has a slope of 3 and passes through the point (1, -1).

Mathematics
1 answer:
andrezito [222]3 years ago
8 0

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

We have the slope m=3\to y=3x+b

and point (1, -1). Substitute:

-1=3(1)+b

-1=3+b      <em>subtract 3 from both sides</em>

-4=b\to b=-4

Answer: y=3x-4

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3 years ago
Find an equation for the line below.
tekilochka [14]

Answer:

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Step-by-step explanation:

This is a straight line, so it would follow the equation y=mx+b. You can find the b value by looking at the y-intercept of the equation (where x=0), which in this case would be -2.5. Then, you can find the m value by comparing the two given points' locations. Slope is rise over run, so first you can find the rise. The y value moves from y=-4 to y=2, which is a value of 6 units upward. The points move from x=-2 to x=6, which is a distance of 8 units. Finally, put it into the rise over run pattern, giving you 6/8, which simplified is 3/4. This is your m value. Finally, plug in your two variable values into y=mx+b and you'll get y=3/4x-2.5.

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3 years ago
What is the distance between (-6, 2) and (8, 10) on a coordinate grid?
lawyer [7]

Answer:

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Step-by-step explanation:

Plug ( -6, 2) and (8, 10) into the distance formula and solve.

Distance = the square root of ((x2 - x1)^2 + (y2 - y1)^2))

Distance = the square root of ((8 - -6)^2 + (10 - 2)^2))

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5 0
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koban [17]

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Step-by-step explanation:

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2 years ago
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AlekseyPX

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8 0
3 years ago
Read 2 more answers
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