Ask question

Ask question

All categories

3 years ago

6

A mixture contains two or more substances chemically combined while a compound contains two or more substances physically combin

ed. True False

1 answer:

Alex73 [517]3 years ago

6 0

True I'm pretty sure

You might be interested in

what is the temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr if it occupies 13.3L at 55 degrees Celsius and 7

Rus_ich [418]

Answer:

3 °C

Explanation:

The pressure is constant, so this looks like a case where we can use Charles’ Law:

$\frac{ V_{1} }{T_{1}} = \frac{V_{2} }{T_{2}}$

Invert both sides of the equation.

$\frac{T_{1} }{V_{1}} = \frac{T_{2} }{V_{2}}$

Multiply both sides by <em>V</em>₂

$T_{2} = T_{1} \times \frac{V_{2} }{ V_{1} }$

<em>V</em>₁ = 13.3 L; <em>T</em>₁ = (55 + 273.15) K = 328.15 K

<em>V</em>₂ = 11.2 L; <em>T</em>₂ = ?

$T_{2} = \text{328.15 K} \times \frac{\text{11.2 L} }{\text{13.3 L}} = \text{276 K} = 3 ^{\circ}\text{C}$

8 0

3 years ago

Which of the following are examples of an Element?

photoshop1234 [79]

Answer:

B. Substance 1 and 3.

Explanation:

1 and 3 and the elements oxygen and helium. 2 is water, a compound, and 4 is table salt, another compound

6 0

3 years ago

Read 2 more answers

The compound MgF is an example of a(n)

Delvig [45]

MgF is an ionic compound because it's bond is between a metal and a non-metal

7 0

3 years ago

Help !! Im not sure how to do this

7nadin3 [17]

1)The third equation must be halved.
H20–>H2+1/2O2
So ΔΗ3=483.6/2
2)The second equation must be halved and reversed.
CO2–>CO+1/2O2
So ΔΗ2=-(-566)/2=566/2

And now :
C+O2–>CO2
CO2–>CO+1/2O2
H2O—>H2+1/2O2
(You add them)
C+H2O—>CO+H2
ΔΗrxn=ΔΗ1+ΔΗ2’+ΔΗ3’=-393.5+283+241,8=131,3

4 0

3 years ago

Determine the mass of chloride (mw = 35.45 g/mol ) in grams present in 100 ml of a 0.325 m solution of aqueous ticl3 (titanium(i

Lana71 [14]

The mass chloride is 3.456 grams

calculation

Step:1 calculate the moles of TiCl3

moles = molarity x volume in liters

volume in liters = 100 ml /1000 = 0.1 L

molarity = 0.325 M = 0.325 mol / L

moles is therefore = 0.1 L x 0.325 mol /L = 0.0325 moles

step 2: find the moles of Cl

since there is 3 atoms of cl in TiCl3 the moles of Cl

= 3 x 0.0325 =0.0975 moles

Step 3: calculate mass of cl

mass= moles x molar mass

=0.0975 moles x 35.45 g/mol = 3.456 g

4 0

3 years ago