Of what?
Attach a link or pic
22.4L.
This is because the standard conversion factor for Liters is 22.4 and in the question it explicitly states liters of CO2.
Therefore, in order to convert Liters of CO2 to Moles of CO2, you'd need to use the conversion factor of 22.4.
Hope this helps!
I believe the answer is A) light; chemical
Answer:- 12.7%
Solution:- It says, ammonium phosphate is 60.9%. It means if we assume 100 g of the sample then there is 60.9 g ammonium phosphate in it.
Formula of ammonium phosphate is
and it's molecular weight is 149 grams per mol. There is only one P in the formula and so the mass of P in 149 g of ammonium phosphate is 31 g(atomic mass of P).
Now, we could use the proportions to find out the mass percentage of P in the sample.
31 g P is present in 149 g of ammonium phosphate, how many grams of P would be present in 60.9 g of ammonium phosphate. Let's set the proportions as:



This 12.7 g of phosphorous is present in 100 g of the sample means there is 12.7% phosphorous in the sample.
Bsbdjxjxnamizizs brush’s ebeidhcycyudejej ehducudidksne r