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shtirl [24]
3 years ago
6

The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol. How much energy is produced by burning 0.8210 g

of naphthalene?
Chemistry
1 answer:
bazaltina [42]3 years ago
3 0

The energy produced by burning : -32.92 kJ

<h3>Further explanation</h3>

Delta H reaction (ΔH) is the amount of heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The enthalpy and heat(energy) can be formulated :

\tt \Delta H=\dfrac{Q}{n}\rightarrow n=mol

The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol.

The energy released for 0.8210 g of naphthalene :

\tt Q=\Delta H\times n\\\\Q=-5139.6~kJ/mol\times \dfrac{0.8210~g}{128.17~g/mol}~\\\\Q=-32.92~kJ

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when naoh(aq) reacts completely with hcl(aq) and resulting solution is evaporated to dryness the solid remaining is?
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3 years ago
Determine the electron geometry, molecular geometry, and idealized bond angles for each molecule. In which cases do you expect d
Ira Lisetskai [31]

Answer:

The electron geometry, molecular geometry and idealized bond angles for these molecules respectively are:

a. CF4: tetrahedral, tetrahedral and 109.5 degrees

b. NF3 tetrahedral, trigonal pyramidal and 102.5 degrees

c. OF2 tetrahedral, angular and 103 degrees

d. H2S tetrahedral, angular and 92.1 degrees

Explanation:

The electron geometry considers the bound atoms and unbound electron pairs to determine the geometry. The four molecules have four bound atoms and/or unbound electrons pairs, thus they have a tetrahedral geometry. On the other hand, the molecular geometry only considers the position of bound atoms to determine the geometry.

Between H3O and H2O, H2O has a smaller bond angle due to the two unbound electron pairs. The bond angle decrease as the number of unbound electron pairs increases in every molecule.

CO2 and CCl4 are both nonpolar because of the 3D geometry of the molecule. Each individual bond is polar but both molecules have symmetrical geometry so the dipole bonds are canceled.

CH3F  is a polar molecule because the dipole between the C-H and C-F bonds are differents thus, besides the symmetrical geometry the dipole bonds are not canceled.

8 0
3 years ago
a 3.81 g sample of NaHCO3 was completely decomposed. After decomposition, Na2CO3 had mass of 2.86g. Determine mass of H2CO3 prod
qaws [65]

Answer:

1.67g H2CO3 are produced

Explanation:

Based on the reaction:

2NaHCO3 → Na2CO3 + H2CO3

<em>2 moles of NaHCO3 produce 1 mole of Na2CO3 and 1 mole of H2CO3</em>

To solve this question we need to find the moles of Na2CO3 = Moles of H2CO3. With their moles we can find the mass of H2CO3 as follows:

<em>Moles Na2CO3 -Molar mass: 105.99g/mol-</em>

2.86g Na2CO3 * (1mol/105.99g) = 0.02698 moles Na2CO3 = Moles H2CO3

<em>Mass H2CO3 -Molar mass: 62.03g/mol-</em>

0.02698 moles  * (62.03g/mol) =

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8 0
3 years ago
PLEASE I REALLY NEED ANSWER REAL QUICK
DENIUS [597]

Answer:

b. 760 g

Explanation:

The mass of the solution = 800 g

5% of NaCl by mass of the solution can be determined as follows;

    5% of 800  =  \frac{5}{100} × 800

                       = 5 × 8

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The mass of NaCl in the solution is 40 g.

The mass of water = mass of solution - mass of NaCl

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                              = 760 g

Therefore, the mass of water required is 760 g.

5 0
3 years ago
What are the 3 states of matter​
dmitriy555 [2]

Explanation:

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4 0
3 years ago
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