Answer: it should be in your reference table
I don’t have an earth science table with me but it is a whole page of wind belts
Explanation:
4. True
5. The amplitude of the ripples decreases as the circumference of the circle increases.
<h3>What is a wave?</h3>
A wave is a disturbance that moves energy from one place to another.
Radio waves, gamma-rays, visible light, and all the other parts of the electromagnetic spectrum are electromagnetic radiation. Electromagnetic radiation can be described in terms of a stream of mass-less particles, called photons, each travelling in a wave-like pattern at the speed of light. Hence, the statement is true.
As the disturbance moves outwards the energy it carries is spread over a larger and larger region called the wavefront. For example, the ripples in the water lie in a circle with an ever-increasing circumference. The amplitude of the ripples decreases as the circumference of the circle increases.
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Answer=3
<span>Decomposition, double replacement, and synthesis are 3 types of chemical reactions.</span>
The answer is true, catalysts increase rates by lowering the activation energy of a reaction. Catalysts lower the reaction energy and so the reaction occurs faster. Enzymes perform the role of biological catalysts. Most metabolic pathways of the body are controlled by enzymes. Enzymes by classification are proteins. <span />
Answer:
The emf of the electrochemical cell has been calculated to be <u>3.364.</u>
in order to calculate the emf we need to apply Nernst equation.
The emf has been the potential of the cell in the reaction with the change in the electrons in the reaction. The emf of the cell has been given by the Nernst equation as -
emf= E⁰ cell - 0.059/n. log 1/concentration
Computation for the emf of the cell
The given cell has the number of electrons transfer, n= 2
The concentration of Pb2= 0.57 M
The concentration of H= 0.090 M
The cell potential of the reaction has been= -0.126
Substituting the values for the emf of the cell:
emf= -0.126- 0.059/2 * log 1/ [0.57]x [0.090] ²
emf= 1.555* 2.337
emf=3.634 v
The emf of the electrochemical cell has been calculated to be 3.634 v.
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