Whats the difference 5 2/7

Maria runs 7 miles in 80 minutes. at the same rate, how many miles would she run in 64 minutes

Alex777 [14]

Answer:

5.6 miles

Step-by-step explanation:

Firstly, we need to find the unit rate (the number of miles in 1 minutes).

To get this, we need to divide total miles ran (7 miles) by the total minutes taken (80 minutes). Thus, we will have MILES PER MINUTE.

7 miles ÷ 80 minutes = 7/80 miles per minute

Now,

We want number of miles in 64 minutes. Since we know "PER MINUTE", we simply multiply that with 64 to get number of miles in that amount of time.

THus,

$\frac{7}{80}*64=\frac{56}{10}=5.6$

So, in 64 minutes, Maria can run 5.6 miles

6 0

3 years ago

Gracie, Mary, and Nancy each have a small collection of seashells. Gracie has 5 more than times the number of shells Mary has. N

Zielflug [23.3K]

Answer:

3/2 x +1 = 5/4x - 5

3/2 x+1 =5/4

x−5

Step 1: Subtract 5/4x from both sides.

3/2 x+1−5/4

x=5

4x−5−5/4x

1/4x+1=−5

Step 2: Subtract 1 from both sides.

1/4x+1−1=−5−1

1/4

x=−6

Step 3: Multiply both sides by 4.

4*(1/4x)=(4)*(−6)

x=−24 Mary has 24 shells

Answer:

-x=−24

x = 24 shells

Step-by-step explanation:

1. 2 3/4 x 16 = 44 + 6 = 50 shells x= 16

2 3/4 x 24 = 66 + 6 = 72 x = 24

We see the side workings in bold as if Mary has 24 and Nancy has 1x more

Then Nancy 24+24 = 48 where Gracie 5 x 24 = 120 and we have 72-48 = 24 and 120-72 = 48 being the same as Nancy. You can ignore or check the rest in explanation.

2 3/4 x 18 = 49 1/2 + 6 = 55 1/2 x= 18

2. 2 3/4 x 16 = 44 -4 = 40 shells x = 16 2 3/4 x 24 = 66 - 4 = 62 x = 24

2 3/4 x 18 = 49 1/2 - 4 = 45 1/2 x = 18

3. 2 3/4 x 16 = 44 + 4 = 48 shells x = 16 2 3/4 x 24 = 66 + 4 = 70 x = 24

2 3/4 x 18 = 49 1/2 + 4 =53 1/2 x = 18

4 0

2 years ago

Read 2 more answers

X+4y=4 in slope intercept form

MAXImum [283]

Answer:

Slope: −14y-intercept: (0,1)

Step-by-step explanation:

7 0

2 years ago

2. Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 1

Yuki888 [10]

The area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.

<h3>What is the area of the rectangle?</h3>

It is defined as the space occupied by the rectangle, which is planner 2-dimensional geometry.

The formula for finding the area of a rectangle is given by:

Area of rectangle = length × width

The dimensions of the garden = 10 ft by 12 ft

Area = 10×12 = 120 square feet

The width of the walkway = 3 feet

If we create a walkway around the garden, it will be a rectangle around the garden.

So the dimensions for the bigger rectangle = (3+10+3) ft by (3+12+3) ft

Area of the bigger rectangle = 16×18 = 288 square feet

So the area of the walkway = 288 - 120 = 168 square feet

Thus, the area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ1

4 0

1 year ago

CAN SOMEONE PLEASE PLEASE PLEASE HELP ME, YOU’LL GET FREE EASY POINTS IF YOU GIVE ME THE RIGHT ANSWER !!

bekas [8.4K]

Answer:

reflection across BC
the image of a vertex will coincide with its corresponding vertex
SSS: AB≅GB, AC≅GC, BC≅BC.

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

__

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

__

The markings on the figure show the corresponding parts to be ...

side AB and side GB
side AC and side GC
angle ABC and angle GBC
angle BAC and angle BGC

And the reflexive property of congruence tells us BC corresponds to itself:

side BC and side BC

There are four available congruence theorems applicable to triangles that are not right triangles

SSS -- three pairs of corresponding sides
SAS -- two corresponding sides and the angle between
ASA -- two corresponding angles and the side between
AAS -- two corresponding angles and the side not between

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

Corresponding sides are listed above. Here, we list them again:

AB and GB; AC and GC; BC and BC

SAS

One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

3 0

1 year ago

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Whats the difference 5 2/7 - 3 4/7