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OLEGan [10]
3 years ago
6

Whats the difference 5 2/7 - 3 4/7

Mathematics
1 answer:
umka21 [38]3 years ago
4 0
5  \frac{2}{7} - 3\frac{4}{7} =\frac{(5\times 7)+2}{7} -\frac{(3\times7)+4}{7} =\frac{37}{7} -\frac{25}{7} -\frac{37-25}{7} =\frac{12}{7}=\boxed{\bf{1\frac{5}{7}}}
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Step-by-step explanation:

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stellarik [79]

Answer:

- 7y +3 =-25

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Step-by-step explanation:

Take +3 to the side so that your variable and a constant is on their own sides. When a number goes over the equals sign the sign changes at becomes the inverse that's why l said - 3. You now calculate - 25—3 equals 28 then divide by 7 to find y and your y is 4.

3 0
3 years ago
What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?
Leno4ka [110]
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hmmm what's the radius anyway?   well, we know that there's a point at 1,2 that is on the circle's path...hmmmm what's the distance from the center to that point?  well, is the radius, let's check then.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -3}}\quad ,&{{ -1}})\quad 
%  (c,d)
&({{ 1}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
r=\sqrt{[1-(-3)]^2+[2-(-1)]^2}\implies r=\sqrt{(1+3)^2+(2+1)^2}
\\\\\\
r=\sqrt{16+9}\implies r=\sqrt{25}\implies r=5

so, what's the equation of a circle with center at -3, -1 and a radius of 5?

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{\quad  k}})\qquad 
radius=&{{ r}}\\
&-3&-1&5
\end{array} 
\\\\\\\
[x-(-3)]^2+[y-(-1)]^2=5^2\implies (x+3)^2+(y+1)^2=25
7 0
3 years ago
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