Shade the decimal 0.6 x 2.2

Solve with the law of sine

Zinaida [17]

1) Triangle QRT, where q = 32.4 ft, r = 29.8 ft, t = 42.1 ft

No this cannot make a second triangle

2) Triangle ABC, where B = 62°, a = 11.52 m, c = 19.34 m

No this cannot make a second triangle

3) Both of the triangles cannot make a second triangle

The following is a detailed explanation of the sine law: In a triangle, side "a" divided by angle sine "a" equals side "b" divided by angle sine "b" equals side "c" divided by angle sine "c."

The formula for law of sine is written as

Sine A a = Sine B/ b = Sine C / c

These law helps in determining the given angles and sides

For the situation given; both cannot be used to make a second triangle

Learn more about conditions Infinite number of triangles at:

brainly.com/question/29637739

#SPJ1

5 0

1 year ago

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

3 years ago

Someone please help

nika2105 [10]

Answer:

b

Step-by-step explanation:

i dont kno lol

6 0

3 years ago

A man earns $ 1200 and spends $ 450 per month. Find the ratio of his saving to his income.

nasty-shy [4]

income =$1200

expenditure=$450

saving=$1200-$450

=$750

ratio of income to expenditure is 1200:450

=8:3

ratio of savings to income is 750:1200

=5:8

hope it helps

mark the BRAINLIEST plzz

5 0

2 years ago

Solve for y -3y-12=-4

Brilliant_brown [7]

Answer:

−8/3

Step-by-step explanation:

Step 1: Add 12 to both sides.

−3y−12+12=−4+12

−3y=8

Step 2: Divide both sides by -3.

−3y−3=8−3

y=−8/3

8 0

2 years ago