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yan [13]
3 years ago
6

Point C is located in which quadrant? a.) I b.) II c.) III d.) IV

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
6 0
B, it is located on the 2nd quadrant
Vikentia [17]3 years ago
6 0
Quadrant IV
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Simplify radicals problems attached please help!
Finger [1]

Answer:

  G7.  (2√3)/3

  G8.  -2+√7

  G9.  (6 +2√2 -3√3 -√6)/7

Step-by-step explanation:

G7.

\dfrac{2}{\sqrt{3}}=\dfrac{2}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}

__

G8.

\dfrac{3}{2 +\sqrt{7}}=\dfrac{3}{2+\sqrt{7}}\cdot\dfrac{2-\sqrt{7}}{2-\sqrt{7}}=\dfrac{6-3\sqrt{7}}{2^2-(\sqrt{7})^2}\\\\=\dfrac{6-3\sqrt{7}}{-3}=\sqrt{7}-2

__

G9.

\dfrac{2-\sqrt{3}}{3-\sqrt{2}}=\dfrac{2-\sqrt{3}}{3-\sqrt{2}}\cdot\dfrac{3+\sqrt{2}}{3+\sqrt{2}}=\dfrac{(2-\sqrt{3})(3+\sqrt{2})}{9-2}\\\\=\dfrac{6+2\sqrt{2}-3\sqrt{3}-\sqrt{6}}{7}

_____

<em>Comment on the problems</em>

In most cases, these expressions are the simplest possible (take the least amount of ink to draw, and take the fewest math operations to evaluate). What seems to be intended is that the denominator be made a rational number. This is done by multiplying the given fraction by a fraction equal to 1 that has the same denominator but with the sign of the radical reversed (unless, as in the first case, the radical is by itself).

The purpose of doing this is to take advantage of the fact that (a-b)(a+b) = a²-b², so if "a" or "b" is a square root, that root will not be seen in the product. In problem G9, we see this can make the numerator quite messy--not exactly a simpler form--but all the irrational numbers are in the numerator.

8 0
3 years ago
How many ways can 4 candy bars be chosen from a store that sells 30 candy bars (combination)
Morgarella [4.7K]

Answer:

Using the combination formula:

Number of combination of r object chosen from the total object i.e n is given by:

\frac{n!}{r! \cdot (n-r)!}

As per the statement:

4 candy bars be chosen from a store that sells 30 candy bars

Number of candy bars chosen from a store that sells 30 candy bars(r)= 4

and

Total candy bars(n) = 30

then substitute in the given formula we have;

\frac{30!}{4! \cdot (30-4)!}

⇒\frac{30!}{4! \cdot (26)!}

⇒\frac{30 \cdot 29 \cdot 28 \cdot 27 \cdot 26!}{1 \cdot 2 \cdot 3 \cdot 4 \cdot (26)!}

Simplify:

⇒\frac{657720}{24} = 27,405

therefore, 27,405  ways can 4 candy bars be chosen from a store that sells 30 candy bars

3 0
3 years ago
Read 2 more answers
Factor the expression completely 8y - 36
Marina86 [1]

ALL yourr doing is just adding 8 and 36

y= 4\frac{1}{2} or y= 4.5

8 0
3 years ago
Read 2 more answers
Which is the product of 7/9 and 6 in a fraction
dybincka [34]

Answer: 14/3

Step-by-step explanation: (7/9) (6) = 54/9 = 14/3

3 0
3 years ago
Given Ohm's Law, V=IR<br> which of the following operations will solve for I?
vodka [1.7K]

FOLLOW ME FOR CLEARING YOUR NEXT DOUBT

8 0
3 years ago
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