Consider the equation:

Subtracting '4' from both the sides of the equation, we get as


Squaring on both the sides of the equation, we get


Subtracting '2' from both the sides of the equation, we get

x=14
Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.
Hence, it is not an extraneous solution.
Answer:
True
Step-by-step explanation:
Answer: x^2 -3
That's x squared minus three
Step-by-step explanation:
When you divide 2x^3 by 2x the 2's cancel, and x cubed becomes x squared.
In 6x divided by 2x, the X's cancel and 6 ÷2=3
BTW "cancels" means that a number divided by itself equals one, so it "disappears" from the expression
126/10 would mean that from the original number, the decimal point is at 126.0 so when it is divided by 10, it will move over one placement, making it 12.6... I would estimate that your answer is C. 12.6