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3 years ago

What tools do scientists use to investigate the natural world

Chemistry

1 answer:

Leya [2.2K]3 years ago

3 0

They use many tools depending on what they want to investigate hopefully this helped!

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What is the molarity of NaOH solution if 30.0g of NaOH solid was dissolved in 500.ml of water? (molar mass of NaOH is 40.0 g/mol

vivado [14]

Answer:

The answer to your question is: 1.5 M

Explanation:

Data

MW NaOH = 40 g/mol

mass = 30 g

V = 500 ml

Molarity (M) = ?

number of moles = n

Formula

M = n/V(l)

Process

40 g ------------------- 1 mol

30 g --------------------- x

x = (30)(1)/40

x = 0.75 mol

Volume

1000 ml ----------------- 1 l

500 ml ---------------- x

x = (500)(1) / 1000

x = 0.5 l

Molarity = 0.75 / 0.5

= 1.5 M

7 0

3 years ago

A solution is prepared from 26.7 g of an unknown compound and 116.2 g acetone, C3H6O, at 313 K. At this temperature the vapor pr

Cloud [144]

Answer:

The molecular weight of the unknown compound is 267.7 g/mol

Explanation:

Lowering vapor pressure → Colligative property where the vapor pressure of solution is lower than vapor pressure of pure solvent

ΔP = P° . Xm

0.526 atm - 0.501 atm = 0.025atm

0.025 atm = 0.526 atm . Xm

Xm = 0.025 atm / 0.526 atm → 0.0475 (mole fraction)

Mole fraction = Moles of solute / Total moles (solute + solvent)

0.0475 = Moles of solute / Moles of solute + Moles of solvent

We determine the moles of solvent → 116.2 g . 1mol / 58 g = 2 moles

0.0475 = Moles of solute / Moles of solute + 2

0.0475 moles of solute + 0.095 = Moles of solute

0.095 = Moles of solute - 0.0475 moles of solute

0.095 / 0.9525 = Moles of solute → 0.0997 moles

Molas mass = g/mol → 26.7 g / 0.0997 mol = 267.7 g/mol

4 0

3 years ago

How many moles are in 2.3x1024 g of Ag?<br> Plz help!!

ziro4ka [17]

Answer:

2.13 × 10²² moles

Explanation:

Relation between Mole and Mass is,

Mole = Mass / M.Mass

Putting values,

Mole = 2.3 × 10²⁴ g / 107.87 g/mol

Mole = 2.13 × 10²² moles

7 0

2 years ago

Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h b

iragen [17]

$C_{x}H_{y} + O_{2} --\ \textgreater \ x CO_{2} + \frac{y}{2} H{2}O

540mg H_{2}O* \frac{1 mmol H_{2}O}{18 mg H_{2}O} =30 mmol H_{2}O

\\ \\30 mmolH_{2}O -have - 60 mmol H
\\ \\ 60 mmol H* \frac{1mg H}{1 mmol H} =60 mg H
\\ \\300mg C_{x}H_{y} - 60 mg H= 240 mg C
\\ \\ 240 mgC* \frac{1mmol}{12mg} =20 mmol C

20 mmol C: 60 mmol H=1 mol C : 3 mol H

$

7 0

4 years ago

Water boils at rate of ........and freeze at ........

Schach [20]

100 degree celcius and 0 degree Celsius

7 0

3 years ago