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MakcuM [25]
3 years ago
11

A force is applied to an object on a frictionless surface. it produces an acceleration of 3m/s2.

Chemistry
1 answer:
Anit [1.1K]3 years ago
4 0
Answer:

no

explanation:

why
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A mixture of hydrogen and argon gases is maintained in a 6.47 L flask at a pressure of 3.43 atm and a temperature of 85 °C. If t
11Alexandr11 [23.1K]

Answer:

The mixture contains 8.23 g of Ar

Explanation:

Let's solve this with the Ideal Gases Law

Total pressure of a mixture = (Total moles . R . T) / V

We convert T° from °C to K → 85°C + 273 = 358K

3.43 atm = (Moles . 0.082 L.atm/mol.K . 358K) / 6.47L

(3.43 atm . 6.47L) / (0.082 L.atm/mol.K . 358K) = Moles

0.756= Total moles from the mixture

Moles of Ar + Moles of H₂ = 0.756 moles

Moles of Ar + 1.10 g / 2g/mol = 0.756 moles

Moles of Ar = 0.756 moles - 0.55 moles H₂ → 0.206

We convert the moles to g → 0.206 mol . 39.95 g / 1 mol = 8.23 g

8 0
3 years ago
Read 2 more answers
Name the following ketone:
alekssr [168]
A. cyclohexyne is the answer
5 0
3 years ago
The sample of 15.0 g of KCl is dissolved into a solution with a total volume of 250.0 mL. What is the molarity of KCl in the sol
lina2011 [118]

Answer:

0.805 M.

Explanation:

Hello!

In this case, since the molarity of a solution is computing by dividing the moles of solute over the volume of solution in liters (M=n/V), for 15.0 g of potassium chloride (74.55 g/mol) we compute the corresponding moles:

n=15.0gKCl*\frac{1molKCl}{74.55gKCl}=0.201molKCl

Next, since the volume is 0.2500 in liters, the molarity turns out:

M=\frac{0.201mol}{0.2500L} \\\\M=0.805M

Best regards!

3 0
3 years ago
If an object has a mass of 20 kg, what is the force of gravity acting on it on earth? A. 196 N B. 32.67 N End of exam C. 1.96 kg
garri49 [273]
Force = mass x gravity

Force = 20 kg x 9.8 m/s²

Force = 196 Newtons

Answer A

hope this helps!

7 0
3 years ago
16. If the velocity of hydrogen molecule is 5 x 10^4cm sec-¹, then its de Broglie wavelength is
Aleks04 [339]

Answer:

Correct option is B)

According to de-Broglie, 

λ=mvh=6.023×10232×5×104cm/sec6.62×10−27ergsec=4×10−8cm=4Ao

5 0
2 years ago
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