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tresset_1 [31]
4 years ago
8

Enzymes increase the rate of a reaction by __________? (A) Contributing water to the reaction. (B) Contributing electrons to the

reaction. (C) Changing the pH of the substrates. (D) Decreasing activation energy. (E) Increasing the temperature of the substrates.
Chemistry
2 answers:
Hatshy [7]4 years ago
3 0
E. Increasing the temperature of the substrates 

The reaction rate increases as the temperature is raised. The increased temperature comes from an increase in kinetic energy. Enzymes are efficient catalysts for reactions, and due to the shape of the molecules in an enzyme, they are selective as to which reactions they catalyze. 
erik [133]4 years ago
3 0
D, enzymes are catalysts and catalysts work by decreasing activation energy required and therefore increasing rate of reaction.
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Given thatH2(g) + F2(g) -> 2HF(g) => ∆H = -546.6 kJ . mol-12H2(g) + O2(g) -> 2H20(l) => ∆H = -571.6 kJ. mol-1
Fantom [35]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -521.6 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the reaction of fluorine and water follows:

2F_2(g)+2H_2O(l)\rightarrow 4HF(g)+O_2(g)   \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) H_2(g)+F_2(g)\rightarrow 2HF(g)    \Delta H_1=-546.6kJ    ( × 2)

(2) H_2(g)+O_2(g)\rightarrow 2H_2O(g)    \Delta H_2=-571.6kJ

The expression for enthalpy of reaction follows:

\Delta H^o_{rxn}=[2\times \Delta H_1]+[1\times (-\Delta H_2)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(2\times (-546.6))+(1\times (571.6))]=-521.6kJ

Hence, the \Delta H^o_{rxn} for the reaction is -521.6 kJ.

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