The distance between two consecutive compressions or rarefactions in a wave is called wavelength.
Answer:
ΔU = - 9,179 10-11 J
Explanation:
For this exercise the two basketballs are linked by gravitational interaction, so we can use gravitational energy
U = - G m₁m₂ / R
In this case the mass is equal and the initial distance is r₁ = 19 cm = 0.19 m
U₁ = - G m² / r₁
let's calculate
U₁ = - 6.67 10⁻¹¹ 0.55² / 0.19
U₁ = - 10,619 10⁻¹¹ J
when its centers are separated it is at r₂ = 1.4 m
U₂ = - 6.67 10⁻¹¹ 0.55² / 1.4
U₂ = - 1.44 10-11 J
the energy between these two points is
ΔU = U₂ - U₁
ΔU = (-1.44 +10.619) 10-11
ΔU = - 9,179 10-11 J
Answer: 60 times brighter
Explanation:
(a) Draw a free body diagram of the cylinder at the top of the loop. At the minimum speed, the normal force is 0, so the only force is weight pulling down.
Sum of forces in the centripetal direction:
∑F = ma
mg = mv²/RL
v = √(g RL)
(b) Energy is conserved.
EE = KE + RE + PE
½ kd² = ½ mv² + ½ Iω² + mgh
kd² = mv² + Iω² + 2mgh
kd² = mv² + (m RC²) ω² + 2mg (2 RL)
kd² = mv² + m RC²ω² + 4mg RL
kd² = mv² + mv² + 4mg RL
kd² = 2mv² + 4mg RL
kd² = 2m (v² + 2g RL)
d² = 2m (v² + 2g RL) / k
d = √[2m (v² + 2g RL) / k]
