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dangina [55]
3 years ago
9

For forces and motion, what is one force that is acting on us right now?

Physics
1 answer:
Verdich [7]3 years ago
7 0

Answer:Gravity

Explanation:

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Starting from rest, a car travels 18 meters as it accelerates uniformly for 3.0 seconds. What is the magnitude of
omeli [17]

Answer:

a=4\frac{m}{s^2}

Explanation:

Hello.

In this case, for this uniformly accelerated motion in which the car starts from rest at 0 m/s and travels 18 m in 3.0 s, we can compute the acceleration by using the following equation:

x_f=x_0+v_0t+\frac{1}{2}at^2

Whereas the final distance is 18 m, the initial distance is 0 m, the initial velocity is 0 m/s and the time is 3.0 s, that is why the acceleration turns out:

a=\frac{2(x_f-v_ot)}{t^2} =\frac{2(18m-0m/s*3.0s)}{(3.0s)^2}\\ \\a=4\frac{m}{s^2}

Best regards.

8 0
4 years ago
This can best be explained due to A) density. B) friction. C) gravity. Eliminate D) inertia.
atroni [7]
What can be explained? Perhaps you could give us the full question?
6 0
3 years ago
Read 2 more answers
Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers
Vedmedyk [2.9K]
First we should convert 14.4 km into meters using the conversion factor 1km = 1000m; thus, 14.4 km = 14,400 m. Next, we should convert all minutes into seconds <span>using the conversion factor 1 min = 60 seconds; thus, 40 mins = 2400 seconds while 20 minutes = 1200 seconds. 
Speed = distance over time
Amy's speed = 14400 m / 2400 sec = 6m/s
Bill's time is 1200 sec + Amy's which is 2400 sec
Bill's speed = 14400m / 3600 sec  = 4 m/s

Therefore, Amy is faster than Bill with 2 m/s difference.</span>
3 0
3 years ago
Which of the following helps in designing an attractive 3-D craft?
MA_775_DIABLO [31]

Answer:

it A texture and colour I

Explanation:

I just did this

5 0
3 years ago
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When landing after a spectacular somersault, a 35.0 kg gymnast decelerates by pushing straight down on the mat. calculate the fo
Sliva [168]

The deceleration experienced by the gymnast is the 9 times of the acceleration due to gravity.

Now from Newton`s  first law, the net force on gymnast,

F_{net} =F-W=ma

Here, W is the weight of the gymnast and a is the acceleration experienced by the gymnast (9\times g acceleration due to gravity)  

Therefore,

F= ma+W OR F=ma+mg=m(g+a)

Given m = 30 kg anda=9\times g=9\times 9.8 m/s^{2} =88.2 m/s^{2}

Substituting these values in above formula and calculate the force exerted by the gymnast,  

F=(40 kg) (88.2 m/s^{2} +9.8 m/s^{2} )

F=3.537\times10^{3}N

6 0
3 years ago
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