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neonofarm [45]
2 years ago
9

D. 'g' vanishes at centre of

Physics
1 answer:
guapka [62]2 years ago
6 0

Answer:

a. 0.8 cm

Explanation:

The distance of the object from the lens, u = 1 cm

The magnification of the lens, m = 5

The focus of a lens formula is given as follows;

f = \dfrac{1}{\dfrac{1}{v} + \dfrac{1}{v}  }

The magnification of the lens, m = -v/u

Where;

v = The distance of the image from the lens

Therefore, we have;

v = m × u

∴ v = 5 × 1 cm = 5 cm (on the other side of the lens)

From which we get;

f = \dfrac{1}{\dfrac{1}{1} + \dfrac{1}{5}  } = \dfrac{5}{6}  \approx 0.8

The focal length ≈ 0.8 cm

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How do y’all solve this
RUDIKE [14]

Answer:

you Subtract

Explanation:

A = 6

B = 6

C = 0

D = 5

9-3= 6

13-7=6

11-11=0

6-1=5

Simple hope it helps

6 0
2 years ago
Read 2 more answers
A cubic meter (m³) is ______ a cubic centimeter (cm³).
valentina_108 [34]

Answer:

C. equal to

Explanation:

1 Cubic meter (m³) is equal to 1000000 cubic centimeters (cm³). To convert cubic meters to cubic centimeters, multiply the cubic meter value by 1000000.

4 0
3 years ago
A 25 kg child plays on a swing having support ropes that are 2.20 m long. A friend pulls her back until the ropes are 42◦ from t
Semmy [17]

Answer:

A) P.E = 138.44 J

B) The velocity of swing at bottom, v = 3.33 m/s

C) The work done, W = -138.44 J

Explanation:

Given,

The mass of the child, m = 25 Kg

The length of the swing rope, L = 2.2 m

The angle of the swing to the vertical position, ∅ = 42°

A) The potential energy at the initial position ∅ = 42° is given by the relation

                                P.E = mgh joule

Considering h  = 0 for the vertical position

The h at ∅ = 42° is  h = L (1 - cos∅)

                               P.E = mgL (1 - cos∅)

Substituting the given values in the above equation

                               P.E = 25 x 9.8 x 2.2 (1 - cos42°)

                                      = 138.44 J

The potential energy for the child just as she is released, compared to the potential energy at the bottom of the swing is, P.E = 138.44 J

B) The velocity of the swing at the bottom.

At bottom of the swing the P.E is completely transformed into the K.E

                  ∴                 K.E = P.E

                                     1/2 mv² = 138.44

                                     1/2 x 25 x v² 138.44

                                            v² = 11.0752

                                             v = 3.33 m/s

The velocity of the swing at the bottom is, v = 3.33 m/s

C) The work done by the tension in the rope from initial position to the bottom

             Tension on string, T = Force acting on the swing, F

                      W=L\int\limits^0_\phi{F} \, d \phi

                             =L\int\limits^0_\phi{mg.sin \phi} \, d \phi

                            = -Lmg[cos\phi]_{42}^{0}

                            = - 2.2 x 25 x 9.8 [cos0 - cos 42°]

                            = - 138.44 J

The negative sign in the in energy is that the work done is towards the gravitational force of attraction.

The work done by the tension in the ropes as the child swings from the initial position to the bottom of the swing, W = - 138.44 J

3 0
3 years ago
What is one advantage of doing a field experiment instead of a laboratory experiment
Flauer [41]

It mimics the real world accurately

Explanation:

Experiments conducted in the field clearly presents the real world at it is to the scientist. Hardly can any part be controlled precisely and this gives a near to perfect scenario.

  • In the laboratory, for example, an organism is isolated from its environment and might not fully display its natural instinct and physiological capabilities.
  • Most laboratory set up are driven towards a model instead of real life settings.
  • The laboratory is more controlled and less varied and might truly represent the real world. It will only portray a part of the real world and series of further tests might have to be carried out to have a better model.

Learn more:

Experiment brainly.com/question/5096428

#learnwithBrainly

5 0
3 years ago
You hear an _____ when sound bounces off a hard surface.
Aleksandr [31]
I think b but I’m not completely sure
7 0
3 years ago
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