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neonofarm [45]
2 years ago
9

D. 'g' vanishes at centre of

Physics
1 answer:
guapka [62]2 years ago
6 0

Answer:

a. 0.8 cm

Explanation:

The distance of the object from the lens, u = 1 cm

The magnification of the lens, m = 5

The focus of a lens formula is given as follows;

f = \dfrac{1}{\dfrac{1}{v} + \dfrac{1}{v}  }

The magnification of the lens, m = -v/u

Where;

v = The distance of the image from the lens

Therefore, we have;

v = m × u

∴ v = 5 × 1 cm = 5 cm (on the other side of the lens)

From which we get;

f = \dfrac{1}{\dfrac{1}{1} + \dfrac{1}{5}  } = \dfrac{5}{6}  \approx 0.8

The focal length ≈ 0.8 cm

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