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neonofarm [45]
3 years ago
9

D. 'g' vanishes at centre of

Physics
1 answer:
guapka [62]3 years ago
6 0

Answer:

a. 0.8 cm

Explanation:

The distance of the object from the lens, u = 1 cm

The magnification of the lens, m = 5

The focus of a lens formula is given as follows;

f = \dfrac{1}{\dfrac{1}{v} + \dfrac{1}{v}  }

The magnification of the lens, m = -v/u

Where;

v = The distance of the image from the lens

Therefore, we have;

v = m × u

∴ v = 5 × 1 cm = 5 cm (on the other side of the lens)

From which we get;

f = \dfrac{1}{\dfrac{1}{1} + \dfrac{1}{5}  } = \dfrac{5}{6}  \approx 0.8

The focal length ≈ 0.8 cm

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Annette [7]
First, determine the mass of the object by dividing its weight on Earth by 9.8 m/s² as shown below,
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Then, multiply the obtained mass by the acceleration due to gravity (g) on Pluto. 
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3 years ago
Four complete waves pass the duck in one second the frequency of this wave is
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A car that increase its speed from 20 km/h to 100 km/h undergoes -------acceleration,
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negative acceleration- deceleration

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A person carries a mass of 10 kg and walks along the +x-axis for a distance of 100m with a constant velocity of 2 m/s. What is t
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The breaking car had 10,000 J of kinetic energy before breaking after breaking it had 2000 J of kinetic energy. How much thermal
WINSTONCH [101]

Answer:

8000J

Explanation:

The kinetic energy of the car lost during breaking are converted to thermal energy and are gained by the brakes.

Kinetic energy loss by car = thermal energy gained by brakes.

∆K.E = ∆T.E ....1

The Kinetic energy loss by car can be expressed as;

∆K.E = K.E1 - K.E2

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Final K.E = K.E2 = 2000J

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From equation 1,

∆K.E = ∆T.E

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