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Greeley [361]
3 years ago
15

Lindsay​ Electronics, a small manufacturer of electronic research​ equipment, has approximately 6 comma 800 items in its invento

ry and has hired Joan​ Blasco-Paul to manage its inventory. Joan has determined that 10​% of the items in inventory are A​ items, 31​% are B​ items, and 59​% are C items. She would like to set up a system in which all A items are counted monthly​ (every 22 working​ days), all B items are counted quarterly​ (every 61 working​ days), and all C items are counted semiannually​ (every 124 working​ days). How many items need to be counted each​ day?
Business
1 answer:
nignag [31]3 years ago
7 0

Answer:

97.8 or 98 items

Explanation:

A items:

= Percent of items in inventory × No. of items

= 0.1 × 6,800

= 680

B items:

= Percent of items in inventory × No. of items

= 0.31 × 6,800

= 2,108

C Items:

= Percent of items in inventory × No. of items

= 0.59 × 6,800

= 4,012

Units to be counted everyday:

=\frac{A\ items}{workings\ days} + \frac{B\ items}{workings\ days} + \frac{C\ items}{workings\ days}

=\frac{680}{22} + \frac{2,108}{61} + \frac{4,012}{124}

      = 30.90 + 34.55 + 32.35

      = 97.8 or 98 items

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Answer:

C(T) = $730 + $25T

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Explanation:

Given that:

C = cost ; R = revenue ; T = number of transactions

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35T = 730 + 25T + 1200

35T - 25T = 730 + 1200

10T = 1930

T = 1930 / 10

T = 193 transactions

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