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Anni [7]
3 years ago
12

he theater club is hosting a one-act competition to raise $1,220 for new costumes. It plans to sell tickets for $8 each and woul

d like to earn within $100 of its goal. This is the equation representing this situation, where t is the number of tickets sold: |8t − 1,220| = 100. Type the correct answer in each box. Use numerals instead of words. To earn within $100 of its goal, the theater club needs to sell a minimum of tickets and a maximum of tickets.

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
7 0

Answer:

140

165

Step-by-step explanation:

To solve the absolute value equation, first rewrite the equation as two separate equations equal to -100 and 100:

8t − 1,220 = -100 8t − 1,220 = 100

8t = 1,120 8t = 1,320

t = 140 t = 165

To earn within $100 of its goal, the theater club needs to sell a minimum of 140 tickets and a maximum of 165 tickets.

Sliva [168]3 years ago
5 0

Answer:

i think that your suppose to divide add and subtracct.

Step-by-step explanation:

Hope this helps.

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PLEASE HELP
elixir [45]

Answer:

Ratio states that it shows the relative sizes of two or more values.

i,e a to b or a: b or \frac{a}{b}

(1)

Given the statement: A zoo has 17 monkeys and 12 chimpanzees

Write this situation in three ways, comparing the first quantity to the second quantity.

By definition of ratio:

Ratio in three ways are:

17 to 12

17 : 12

\frac{17}{12} or we can write this as 17 over 12.

therefore, Option B is correct.

(2)

As per the statement: In Largo City, about one in every nine homes contains four televisions

Write this situation in three ways in the form of ratio, comparing the first quantity to the second quantity.

By definition of ratio:

Ratio in three ways are:

4 to 9

4 : 9

\frac{4}{9}

therefore, only options C is correct.

(3)

write three ratios for 7 over 35

By definition of ratio;

We have;

\frac{7}{35}

Divide both numerator and denominator by 7 we have;

\frac{1}{5}               .....[A]

⇒ \frac{7}{35} =\frac{1}{5}

Multiply both numerator and denominator by 2 in A we get;

\frac{1}{5} = \frac{1 \times 2}{5 \times 2} = \frac{1}{10}

Similarly,

Multiply both numerator and denominator by 3 in A, we get

\frac{1}{5} = \frac{1 \times 3}{5 \times 3} = \frac{3}{15}

Therefore, 3 ratios equal to  7 over 35 are;

\frac{1}{5} or we can write it as one-fifth

\frac{2}{10} or two -tenths

\frac{3}{15} or three over fifteen

hence, Option D is correct.

(4)

Given the statement: Jake sold 28 tickets to the school fair, and Jeanne sold 21 tickets

Number of ticket Jake sold = 28 ticket.

Number of ticket Jeanne sold = 21 ticket.

To find: Number of ticket Jeanne sold to number of ticket Jake sold.

By definition of ratio

⇒\frac{21}{28}

Therefore, the ratio in simplest form is, \frac{21}{28}


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