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alexandr1967 [171]
3 years ago
6

Please help me !!

Mathematics
2 answers:
aleksley [76]3 years ago
6 0
1)~3x-7-2x+5=6\iff (3x-2x)+(-7+5)=6\iff\\\\ x-2=6\iff x=6+2\iff\boxed{x=8}\\\\
2)~A(x)=\dfrac{f(2)-f(-5)}{(2)-(-5)}=\dfrac{(2^2+7\cdot2+10)-((-5)^2+7\cdot(-5)+10)}{7}\\\\=\dfrac{(4+14+10)-(25-35+10)}{7}=\dfrac{28-0}{7}=\dfrac{28}{7}=4\iff\boxed{A(x)=4}
lilavasa [31]3 years ago
5 0
Number 1 is x=8!! 


2 is pretty confusing so I hope someone else can answer two as I have answered 1!
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3 years ago
Which function below represents the arithmetic sequence 3, 7, 11, 15...?
mr Goodwill [35]
D) f(n) = 3 + 4(n-1)

3 = 1st term
4 = common difference among the terms
n = term number you are looking for.

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f(1) = 3 + 4(1-1) = 3 + 4(0) = 3 + 0 = 3
f(2) = 3 + 4(2-1) = 3 + 4(1) = 3 + 4 = 7
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4 0
3 years ago
Read 2 more answers
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7 0
3 years ago
Find the amount to which $2,500 will grow if interest of 6.75% is compounded quarterly for 10
andreev551 [17]

Answer:

Part a

For this case n = 4. If we use the future value formula we got:

A= 2500 (1+ \frac{0.0675}{4})^{4*10}= 4882.506

Part b

For this case n = 365. If we use the future value formula we got:

A= 2500 (1+ \frac{0.0675}{365})^{365*10}= 4909.776

Step-by-step explanation:

We can use the future vaue formula for compound interest given by:

A= P(1+ \frac{r}{n})^{nt}

Where P represent the present value, r=0.0675 , n is the number of times that the interest is compounded in a year and t the number of years.

Part a

For this case n = 4. If we use the future value formula we got:

A= 2500 (1+ \frac{0.0675}{4})^{4*10}= 4882.506

Part b

For this case n = 365. If we use the future value formula we got:

A= 2500 (1+ \frac{0.0675}{365})^{365*10}= 4909.776

5 0
3 years ago
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