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gladu [14]
3 years ago
6

57 over 60 as a decimal

Mathematics
2 answers:
Olegator [25]3 years ago
7 0

Answer: 0.95

Here we will simplify 57/60 to its simplest form and convert it to a mixed number if necessary.

In the fraction 57/60, 57 is the numerator and 60 is the denominator.

When you ask "What is 57/60 simplified?", we assume you want to know how to simplify the numerator and denominator to their smallest values, while still keeping the same value of the fraction.

We do this by first finding the greatest common factor of 57 and 60, which is 3.

Then, we divide both 57 and 60 by the greatest common factor to get the following simplified fraction: 19/20

To make it easier, to make 19/20 as a decimal, we can multiply the denominator "20" by 5 making it 100. Since we multiplied the denominator, we also have to do the same to the numerator which in this case is 19 x 5 = 95. So, the fraction will be 95/100 or 0.95.

Contact [7]3 years ago
3 0

Answer:

0.95

Step-by-step explanation:

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In the transformation ABC A'B'C', the preimage of B' is ____. . a0
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<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

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which is a very small number close to zero.</span>
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