Answer:
p = 6.64 cm
Explanation:
For this exercise we use the equation of the constructor

where f is the focal length, p and q are the distance to the object and the image, respectively
They tell us the focal length f = 2.2 cm and that the image as far as it can go is q = 3.29 cm, let's find the position of the object that creates this image
1 / p = 1 / 2.2 - 1/3.29
1 / p = 0.15059
p = 6.64 cm
therefore the farthest distance from the object is 6.64 c
Answer: silicon,or maybe none.
Explanation: I searched it up not really sure sorry
I think its between b or c
I believe the answer your looking for is A. Flammability. Because flammability is a chemical property, not a physical one. Hope this helps :)