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wolverine [178]
3 years ago
15

A boy rides a sled down a steep, snow.covered hill. Which of

Physics
2 answers:
shtirl [24]3 years ago
5 0

Answer:

Potential energy decreases and kinetic energy increases.

Explanation:

That was the answer on my CK12

Travka [436]3 years ago
4 0

Answer:

a. Potential energy decreases and Kinetic energy increases

Explanation:

Because as he comes down due to its steepness the speed of the boy or you can say his KE increases and since he comes from a high position (hill) to the lower ground his potential energy decreases simultaneously

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Humidify your home. ...

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Keep touching metal.

Explanation:hope that helps

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What is the definition for nebula
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A large, metallic, spherical shell has no net charge. It is supported on an insulating stand and has a small hole at the top. A
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Answer:

D) -Q

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3 years ago
A Carnot engine operates between 1350 °F and 125 °F. If it rejects 55 Btu as heat, determine the work output.
ruslelena [56]

Answer:

C. W = 115.12\,Btu

Explanation:

Thermodynamically speaking, a Carnot engine represents an entirely reversible thermal process and its energy efficiency represents the maximum theoretical efficiency that thermal machines can reach. The efficiency of the ideal thermal process (\eta), no unit, is:

\eta = \left(1-\frac{T_{L}}{T_{H}} \right) (1)

Where:

T_{L} - Temperature of the cold reservoir, measured in Rankine.

T_{H} - Temperature of the hot reservoir, measured in Rankine.

If we know that T_{H} = 1809.67\,R and T_{L} = 584.67\,R, then the energy efficiency of the ideal thermal process is:

\eta = 0.678

By First Law of Thermodynamics, we calculate the work output:

W = Q_{H}-Q_{L}

W = \frac{W}{\eta} -Q_{L} (By definition of efficiency)

Q_{L} = \frac{W}{\eta}-W

Q_{L} = \left(\frac{1}{\eta}-1 \right)\cdot W(2)

Where:

Q_{H} - Heat received by the engine, measured in Btu.

Q_{L} - Heat rejected by the engine, measured in Btu.

W - Work output, measured in Btu.

If we know that \eta = 0.678 and Q_{L} = 55\,Btu, then the work output of the Carnot engine is:

W = \frac{Q_{L}}{\frac{1}{\eta}-1 }

W = 115.807\,Btu

The work output of the Carnot engine is 115.807 Btu. (Answer: C)

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3 years ago
A ball is moving at 3 m/s and has a momentum of 48 kg m/s. What is the ball's mass?
jonny [76]
P = mv \\ m =  \frac{P}{v}  \\
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