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2 years ago

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A mass of (200 g) of hot water at (75.0°C) is mixed with cold water of mass M at (5.0°C). The final temperature of the mixture i

s (25.0°C). What is the mass of the cold water (M)?

1 answer:

MArishka [77]2 years ago

3 0

Answer:

500 g

Explanation:

Specific heat of water = 1 j/g-c

Heat given up by hot water = 200(75-25)(1) = 10 000 j

this is the heat GAINED by the cold water

10000 j = x ( 25 -5)(1)

x =500g

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