The launch speed of a horizontally launched projectile is 13.28 m/s.
<h3>
Time of motion of the projectile</h3>
The time of motion is calculated as follows;
t = √(2h / g)
where;
- h is height of the cliff
- g is acceleration due to gravity
t = √(2 x 19.3 / 9.8)
t = 1.98 s
<h3>Launch speed of the projectile</h3>
X = Vxt
Vx = X/t
Vx = (26.3)/(1.98)
Vx = 13.28 m/s
Thus, the launch speed of a horizontally launched projectile is 13.28 m/s.
Learn more about horizontal speed here: brainly.com/question/24949996
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Answer:
The answer to the question is
4433.416 kJ
See explanation below
(3-y)²+r² = 3² or
6y-y² = r²
r =√(6y-y²)
The volume of a small section of height Δy = Δy ×(√(6y-y²))²×π
For water with density of 1000 kg/m³, the mass of the slice
= 1000×Δy ×(√(6y-y²))²×π and since force = mass × acceleration we have
1000×Δy ×(√(6y-y²))²×π ×g = 1000×Δy ×(√(6y-y²))²×π ×9.81
The work done to move a unit height of y+1 = Force × Distance
W = 1000×Δy ×(√(6y-y²))²×π ×9.81 × (y+1)
Integrating the entire section of the sphere that is 2×r high, or from 0 to 6 we get
W =
= 
![= 9810*\pi *[\frac{5y^{3} }{3} -\frac{y^{4} }{4} +3y^{2} ]^{6} _{0}](https://tex.z-dn.net/?f=%3D%209810%2A%5Cpi%20%2A%5B%5Cfrac%7B5y%5E%7B3%7D%20%7D%7B3%7D%20-%5Cfrac%7By%5E%7B4%7D%20%7D%7B4%7D%20%2B3y%5E%7B2%7D%20%5D%5E%7B6%7D%20_%7B0%7D)
=9810×π×144 =4433416 J
When you exert a force on the coin, it will accelerate. If you push the coin and it moves at a constant velocity, the friction force must be equal to the force that you are exerting. This is an example of a balanced force. When the net force is greater than 0 N, the is an unbalanced force.
Answer:
electrical energy change into heat and light energy.
