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astraxan [27]
3 years ago
8

Three values on a number line are labeled F, G, and H . Which number line correctly shows the values of F, G, and H?​

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

F must be on -4

H must be on 4 (because it is -f=-(-4)=-1•-4=4)

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Marshall's office had already recycled 2 kilograms this year before starting the new recycling plan, and the new plan will have
Alona [7]

Answer: w x 4 + 2 = p

Step-by-step explanation:

W = Week

P = Paper

4 kg a week would be 4 x w

you also must add the 2 kilograms at the start of the year

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How do I solve y = a + 151
bulgar [2K]

Answer:I don’t know I’m in sixth grade

Step-by-step explanation:

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The area of a triangle is found by multiplying half of the measure of its base by its height. The area of the following right tr
GarryVolchara [31]

Answer:

\sf Area\:of\:a\:triangle=\dfrac12 \times base \times height

Given:

  • area = 18 cm²
  • base = 6 cm
  • height = (h + 1) cm

Substitute the given values into the equation and solve for h:

\sf \implies 18 = \sf \dfrac12 \times 6 \times (h+1)

\sf \implies 18 = \sf \dfrac62 (h+1)

\sf \implies 18 =3(h+1)

expand using distributive property of addition a(b+c)=ab+ac:

\sf \implies 18=3h+3

subtract 3 from both sides:

\sf \implies 3h=15

divide both sides by 3:

\sf \implies h=5

<u>To verify</u>:

Half of the base is 3 cm.

If h=5, then the height of the triangle is 6 cm.

Multiplying 3 by 6 is 18.

This matches the given area, so we can verify that h = 5.

3 0
2 years ago
Read 2 more answers
What is the perimeter of a rectangle length 86ft width 9ft 10inches?
kondor19780726 [428]

The perimeter is 166.9 ft.

Convert feet to inches to make it easier to calculate. The formula to find the perimeter is... 2(w+h)

once you get your answer, convert inches back to feet.

3 0
2 years ago
The length of a rectangle is 3 inches more than the width. The area is 10 square inches. Find the dimensions
mr_godi [17]

Answer:

Width = 2

Length = 5

Step-by-step explanation:

let A be the area of the rectangle

   L be the length of the rectangle

   w be the width of the rectangle

<u><em>Formula</em></u>: ‘<u><em>area of a rectangle</em></u>’

A = L × w

…………………………………………………

A = L × w

⇔ 10 = (w + 3) × w

⇔ 10 = w² + 3w

⇔ w² + 3w - 10 = 0  

<u><em>Solving the quadratic equation</em></u> w² + 3w - 10 =  0 :

Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49

then √Δ = 7

\Longrightarrow w=\frac{-b+\sqrt{\Delta } }{2a} =\frac{-3+7}{2} =2

  or\ w=\frac{-b-\sqrt{\Delta } }{2a} =\frac{-3-7}{2} =-5

-5 is not valid ,because w represents the width

which must be a positive number

Then  w = 2

<u><em>Conclusion</em></u>:

Width = 2

Length = 2 + 3 = 5

6 0
2 years ago
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