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Vera_Pavlovna [14]
3 years ago
9

The diagram represents a dilation with a center at P. If the scale factor of e dilation is K, which statement about the diagram

is true?

Mathematics
1 answer:
boyakko [2]3 years ago
8 0

Answer:

C is correct. If the scale factor is greater than 1, the image is an enlargement. The segment UT could be an enlargement of the segment ST.

Step-by-step explanation:

A. If > 1, then the image of could be .  

B. If 0 < < 1, then the image of could be . ( If the scale factor is between 0 and 1, the image is a reduction )

C. If > 1, then the image of could be .

D.If = 2, then the image of is itself.

A is not correct.  If the scale factor is between 0 and 1, the image is a reduction.

B is not correct.  If the scale factor is between 0 and 1, the image is a reduction.

C is correct.  If the scale factor is greater than 1, the image is an enlargement.

D is not correct.  If the scale factor is 1, the figure and the image are congruent.

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igor_vitrenko [27]

The expression you have is already in its simplest form. However, there is another way to write it.

m - n/4

This expression is the same as the original, apart from the fact that we wrote the division as a fraction.

4 0
3 years ago
What is -2x-5=4????
cupoosta [38]

Answer:

-9/2

Step-by-step explanation:

-2x-5 = 4

    +5   +5

-2x = 9

------  ------

-2    -2

x = -9/2

7 0
3 years ago
Read 2 more answers
Please help me I’m stuck.
Svetlanka [38]

Answer:

Step-by-step explanation:

We will use the general area formula for finding the area of triangle when you are given information for SAS, which we have been.

A=\frac{1}{2}absinC , where a and b are the given side lengths and C is the included angle. You can ONLY use this when you have the info for SAS in a triangle. For us,

a = 17, b = 15 and C = 35 degrees.  Filling in:

A=\frac{1}{2}(17)(15)sin35

Do that on your calculator in degree mode and you'll find the area to be

73.1 meters squared

6 0
3 years ago
You recently discovered that your job provides a 25% matching towards your retirement.
Harman [31]

Answer:

What is typed in the attached Excel file is =FV(B4,B5,-B3,0,0).

Step-by-step explanation:

Note: See the attached excel file for the calculation of future value of an ordinary annuity.

Since we want to find the balance after 30 years, the function in the Excel is the FV function which is used to calculate the future value (FV) of an ordinary annuity as follows:

=FV(rate,nper,-pmt,0,0) …………………… (1)

rate = Monthly interest rate = APR / 12 = 8.99% / 12 = 0.0899 / 12 = 0.00749166666666667. Note: This is typed in cell B4 in attached excel file.

nper = periods = number of months = 30 years * 12 months = 360. Note: This is typed in cell B5 in attached excel file.

pmt = monthly payment = $300. Note: This is typed in cell B3 in the attached excel file. And also typed as a negative value in cell B7, i.e. as -B3.

pv = present value = 0. Note: This is the first 0 typed in cell B7 in the attached excel file.

type 0 = 0 this is typed to indicate that deposit is made at end of period as a regular or ordinary annuity. This is the second 0 typed in cell B7 in the attached excel file.

Based on the above, the FV function in equation (1) above is converted to the following which is typed in the attached Excel file to find the balance after 30 years:

=FV(B4,B5,-B3,0,0)

The above then gives a future value of $548,080.11 which is  the balance after 30 years.

Download xlsx
3 0
3 years ago
Lily swims for 5 hours in stream that has a current of 1 mph. She leaves her dock, swims upstream for 2 miles and then swim back
antiseptic1488 [7]

Answer:

Swimming speed in still water is approximately 1.5 mph

Step-by-step explanation:

Given the speed of the current = 1 mph

distance she swims upstream =2 miles,

the total time = 5 hours.

She swam 2 miles upstream against the  current and 2 miles back to the dock with  the current. The formula that relates  distance, time, and rate is d = r t\ \ \ \ or  \ \ \  t= \frac{d}{r}

Let x be the speed in still water.

Then  her speed with the current is x + 1, and

her speed against the current is x – 1.

Total time is equal to 2 miles with upstream and 2 miles downstream.

\frac{2}{x+1}+\frac{2}{x-1}=5\\\\\frac{2(x-1)}{(x+1)(x-1)}+\frac{2(x+1)}{(x-1)(x+1)}=5\\\\\frac{2x-2}{(x^2-1)}+\frac{2x+2)}{(x^2-1)}=5\\\\\frac{2x-2+2x+2)}{(x^2-1)}=5\\\\4x=5(x^2-1)\\4x= 5x^2-5\\0= 5x^2-4x-5

Now Using quadratic formula to solve above equation we get;

x= \frac{-b \±\sqrt{b^2-4ac}} {2a}\\\\here \ \ a= 5,b=-4,c=-5\\\\x= \frac{-(-4) \±\sqrt{(-4)^2-4\times 5\times-5}} {2\times5}\\\\x=\frac{4 \±\sqrt{16+100}} {10}\\\\x=\frac{4 \±\sqrt{116}} {10}=x=\frac{4 \±2\sqrt{29}} {10}= x=\frac{2 \±\sqrt{29}} {5}\\ x \approx 1.5 \ or \ x = -0.7

Since speed must be positive, Hence speed of still water is about 1.5 miles per hour.

3 0
3 years ago
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