All categories

3 years ago

Which best describes the projectile motion of the marble as it leaves the table at the two different speeds?

1 answer:

3 0

<span>As the marble leaves the table at two different speeds, its
horizontal velocity changes, but its vertical velocity does not.</span>

You might be interested in

Juan and Kuri are on a carousel. Juan is closer to the center of the carousel than Kuri. Which statement describes their tangent

Licemer1 [7]

Answer:

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

Explanation:

Since Juan is closer to the center and Kuri is away from the center so we can say that Juan will move smaller distance in one complete revolution

As we know that the distance moved in one revolution is given as

$d = 2\pi r$

also the time period of revolution for both will remain same as they move with the time period of carousel

Now we can say that the speed is given as

$v = \frac{2\pi r}{T}$

so Juan will have less tangential speed. so correct answer will be

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

6 0

3 years ago

Read 2 more answers

Squids are the fastest marine invertebrates, using a powerful set of muscles to take in and then eject water in a form of jet pr

tatuchka [14]

Answer:

0.25 m/s

Explanation:

This problem can be solved by using the law of conservation of momentum - the total momentum of the squid-water system must be conserved.

Initially, the squid and the water are at rest, so the total momentum is zero:

$p_i = 0$

After the squid ejects the water, the total momentum is

$p_f = m_s v_s + m_w v_w$

where

$m_s = 1.60 kg$ is the mass of the squid

$v_s$ is the velocity of the squid

$m_2 = 0.115 kg$ is the mass of the water

$v_w = 3.50 m/s$ is the velocity of the water

Due to the conservation of momentum,

$p_i = p_f$

$0=m_s v_s + m_w v_w$

so we can find the final velocity of the squid:

$v_s = -\frac{m_w v_w}{m_s}=-\frac{(0.115 kg)(3.50 m/s)}{1.60 kg}=-0.25 m/s$

and the negative sign means the direction is opposite to that of the water.

8 0

3 years ago

Two blocks are connected by a very light string passing over a massless and frictionless pulley. Traveling at constant speed, th

Semenov [28]

Answer:

Explanation:

Please see attached the diagram and also the FBD for your reference.

Step one:

given data

Weight w1=20N

Distance s1=75cm= 0.75m

Weight w2=12N

Distance s2=75cm =0.75m

Clearly, we are asked to find the work done by gravity and the tension in the string.

we know that work is defined as force times the distance traveled

W=F*D

and to know the force we need the acceleration, seeing that the system is stationary the acceleration due to gravity 9.81m/s^2 is not needed here

i . Work done by gravity = w2*s2=12*0.75=9J

ii. The tension is equal but opposite = -9J

4 0

3 years ago

A subway goes 5 km from the sports complex to downtown in 30 minutes. What is the average speed of the subway? A. 2.5 km/h B. 6

rusak2 [61]

It should be B!!!! Because you are suppose divide30km by 5 which is 6km/h.

8 0

3 years ago

Read 2 more answers

Two flat 4.0 cm × 4.0 cm electrodes carrying equal but opposite charges are spaced 2.0 mm apart with their midpoints opposite ea

Olenka [21]

Answer:

$q =1.07 \times 10^{-7}\ C$

Explanation:

given.

Two flat 4.0 cm × 4.0 cm electrodes carrying equal charge

space between the charges = 2 mm

Electric field strength = 7.6 x 10⁶ N/C

ε ₀ = 8.85 × 10⁻¹² C²/N · m²

magnitude of charge =?

Electric field strength between to two plates

$E = \dfrac{q}{A\epsilon_0}$

$q = E A \epsilon_0$

$q = 7.6 \times 10^6 \times 0.04 \times 0.04 \times 8.85 \times 10^{-12}$

$q =1.07 \times 10^{-7}\ C$

7 0

4 years ago