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Aleksandr-060686 [28]
3 years ago
5

The speed of light in vinegar is 2.30 x 10^8 m/s. Determine the index of refraction. (2​

Physics
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

n _{v} =  \frac{c}{v}  \\  =  \frac{3 \times  {10}^{8} }{2.30 \times  {10}^{8} }  \\  = 1.30

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What ocean depth would the volume of an aluminium sphere be reduced by 0.10%
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Answer:

6400 m

Explanation:

You need to use the bulk modulus, K:

K = ρ dP/dρ

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K ≈ ρ ΔP/Δρ

Therefore, solving for ΔP:

ΔP = K Δρ / ρ

We can calculate K from Young's modulus (E) and Poisson's ratio (ν):

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Substituting:

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After compression:

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ρ+Δρ = m / (0.999 V)

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Given:

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If we assume seawater density is constant at 1027 kg/m³, then:

ρgh = P

(1027 kg/m³) (9.81 m/s²) h = 64.0×10⁶ Pa

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Rounded to two sig-figs, the ocean depth at which the sphere's volume is reduced by 0.10% is approximately 6400 m.

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