Two blocks are connected by a very light string passing over a massless and frictionless pulley. Traveling at constant speed, th
1 answer:
Answer:
<h2>i. 9J and </h2><h2>ii. -9J</h2>Explanation:
Please see attached the diagram and also the FBD for your reference.
Step one:
given data
Weight w1=20N
Distance s1=75cm= 0.75m
Weight w2=12N
Distance s2=75cm =0.75m
Clearly, we are asked to find the work done by gravity and the tension in the string.
we know that work is defined as force times the distance traveled
W=F*D
and to know the force we need the acceleration, seeing that the system is stationary the acceleration due to gravity 9.81m/s^2 is not needed here
i . Work done by gravity = w2*s2=12*0.75=9J
ii. The tension is equal but opposite = -9J
You might be interested in
Answer:
When the tangent of the cyclic frequency and time will be equal √2
Explanation:
