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Goryan [66]
3 years ago
8

Two balls move down a incline. One spins, while the other slides. Which one is going faster at the bottom?

Physics
1 answer:
natta225 [31]3 years ago
7 0

Answer: the one spinnin

Explanation:

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Which is not a characteristic of an ideal fluid?
Lena [83]
The answer would be B
7 0
3 years ago
The speed for a car that went a distance of 125 miles in 2 hours time is ______. Question 2 options: 250 meters/sec 62.5 miles/h
Goryan [66]

Answer:

62.5 miles per hour

Explanation:

Speed = Distance travelled / Time taken

Speed = 125/2 = 62.5

You derive the units of the speed...by using the speed formula....,

Speed = Distance/Time

Speed = miles/hour

Hence the units for the speed = miles/hour

5 0
3 years ago
A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine
bixtya [17]

125 W is the power output of this machine.

Answer:

Explanation:

Power is defined as the amount of work done on the system to move that system from its original state within the given time interval. So it can be determined by the ratio of work done with time interval. As work done is the measure of force required to move a system to a certain distance. Work done is calculated as product of force with displacement.

So in the present case, the force is given as 100 N, the displacement is given as 5 m and the time is given as 4 s, then power is

Power = \frac{Work done}{Time}

As Work done = Force acting on the machine × Displacement

So Power = \frac{(Force * Displacement)}{Time}

Power = \frac{(100*5)}{4}=125 W

So, 125 W is the power output of this machine.

6 0
3 years ago
A spherical mirror gives an image magnified 5 times at a distance 5 m. determine whether the mirror is convex or concave? How mu
irakobra [83]

Answer:

1. Concave mirror.

2. 4.17 m or 417 cm.

Explanation:

The following data were obtained from the question:

Object distance (u) = 5 m

Magnification (M) = 5

Focal length (f) =..?

1. Identification of the mirror.

To determine whether or not the mirror is concave or convex, we must first of all calculate the image distance.

This can be obtained as follow:

Object distance (u) = 5 m

Magnification (M) = 5

Image distance (v) =.?

Magnification (M) = image distance (v) /object distance (u).

M = v/u

5 = v/5

Cross multiply

v = 5 x 5

v = 25 m

Since the image distance obtained is positive, the mirror is said to be a concave mirror.

2. Determination of the focal length of the mirro.

This can be obtained as follow:

Object distance (u) = 5 m

Image distance (v) = 25 m

Focal length (f) =...?

1/f = 1/v + 1/u

1/f = 1/25 + 1/5

1/f = 0.04 + 0.2

1/f = 0.24

Cross multiply

f x 0.24 = 1

Divide both side by 0.24

f = 1/0.24

f = 4.17 m

Converting the focal length of cm, we have:

1 m = 100 cm

Therefore, 4.17 m = 4.17 x 100 = 417 cm

Therefore, the focal length of the mirror is 4.17 or 417 cm.

4 0
3 years ago
Calculate the angular velocity and linea­r velocity of both wheels assuming the l­arger wheel rotates at 120 revolutions p­er mi
IRINA_888 [86]
<span>120 revolutions p­er min is (20RPM)
120revolutions is 240 Pi radians (because 1 revolution is 2Pi rad)

angular velocity
w= 240Pixf, f is the frequency and f= 1/T, T =1mn=60s=period, so f=1/60=0.01Hz
so w = 240*Pi*0.01=12.56 rad /s
linear velocity can be found with
V =Rx w,    
V=12.56 R the value depends on what value is the radius of both wheels

</span>
6 0
3 years ago
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