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liberstina [14]
2 years ago
14

A probability distribution is a listing of all the outcomes of an experiment and the probability associated with each outcome. T

he outcomes are mutually exclusive, and the list of outcomes is exhaustive.
1. True
2. False
Mathematics
1 answer:
Novosadov [1.4K]2 years ago
5 0

Answer:

True.

Step-by-step explanation:

A probability distribution is a listing of all the outcomes of an experiment and the probability associated with each outcome. Probability distribution is associated with the following characteristics or properties;

1. The outcomes are mutually exclusive.

2. The list of outcomes is exhaustive, which simply means that the sum of all probabilities of the outcomes must equal one (1).

3. The probability for a particular value or outcome must be between 0 and 1.

Since a probability distribution gives the likelihood of an outcome or event, a single random variable is divided into two main categories, namely;

I. Probability density functions for continuous variables.

II. Discrete probability distributions for discrete variables.

For example, when a coin is tossed, you can only have a head or tail (H or T).

Also, when you throw a die, the only possible outcome is 1/6 and the total probability for it all must equal to one (1).

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Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

A\cap B={HH}

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A\cap C={HH}

P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

P(A)=\frac{2}{4}=\frac{1}{2}

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Number of favorable cases to event C=2

P(B)=\frac{2}{4}=\frac{1}{2}

P(C)=\frac{2}{4}=\frac{1}{2}

If the two events A and B are independent then

P(A)\cdot P(B)=P(A\cap B)

P(A\cap)=\frac{1}{4}

P(B\cap C)=\frac{1}{4}

P(A\cap C)=\frac{1}{4}

P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}

P(B)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(B)=P(A\cap B)

Therefore, A and B are independent

P(B)\cdot P(C)=P(B\cap C)

Therefore, B and C are independent

P(A\cap C)=P(A)\cdot P(C)

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

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