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Ivanshal [37]
3 years ago
10

EASY QUESTIONS! Whats 1+1?

Mathematics
2 answers:
frozen [14]3 years ago
7 0
Hmm I would have to say I'm sorry if I get this wrong but it's super difficult but I think it's 11?? I'm not sure LOL
lord [1]3 years ago
5 0
The answer would be 2
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Whats the value of x
Gnesinka [82]

Answer:

i think 64?

Step-by-step explanation:

its supposed to be the same on the bottom, right?

3 0
3 years ago
Read 2 more answers
1. A football team charges $30 per ticket and averages 20,000 people per game. Each
IRINA_888 [86]

Question: A Football Team Charges $30 Per Ticket And Averages 20,000 People Per Game. Each Person Spends An Average Of $8 On Concessions. For Every Drop Of $1 In Price, The Attendance Rises By 800 People. What Ticket Price Should The Team Charge To Maximize Total Revenue? Calculate The TR Max.

This problem has been solved!

See the answer

A football team charges $30 per ticket and averages 20,000 people per game. Each person spends an average of $8 on concessions. For every drop of $1 in price, the attendance rises by 800 people. What ticket price should the team charge to maximize total revenue? Calculate the TR max.

$50

                                                                                                                                             

7 0
3 years ago
3/5 and 0.4. Which number is the smallest?
jeyben [28]
0.4 is the answer, 3/5= 0.6
6 0
3 years ago
if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is .....a.2 b.-2 c 1/2 d.none ​
blsea [12.9K]

Answer:

k=2

Problem:

if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is ..

Step-by-step explanation:

Since the coefficient of x^2 is 1, we can use this identity to aid us: x^2+bx+(b/2)^2=(x+b/2)^2.

So we want the following:

[(k+2)/2]^2=2k

Apply the power on the left:

(k+2)^2/4=2k

Multiply both sides by 4:

(k+2)^2=8k

Expand left side:

k^2+4k+4=8k *I used identity (x+c)^2=x^2+2xc+c^2

Subtract 8k on both sides:

k^2-4k+4=0

Factor using the identity mentioned a couple lines above:

(k-2)^2=0

Since zero squared is zero, we want k-2=0.

Adding both sides by 2 gives k=2.

8 0
3 years ago
How do I solve this??
olga_2 [115]

Answer:

Step-by-step explanation:

x + 29 + 12 = 89

x + 41 = 89

x = 48 for <CED

5 0
2 years ago
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