Question

Solve the equation c+(4-3C) -2=0.

Answer 1

$c+(4-3C) -2=0$ 

$c+(4-3C) -2=0:C$   $| Solve \ for \ C|$ 

$c+4-3C-2=0$  $|Simplify \ brackets|$ 

$c-3C+2=0$  $|Simplify|$ 

$-3C+2=-c$  $|Subtract \ c \ from \ both \ sides|$ 

$-3C=-c-2$    $|Subtract \ 2 \ from \ both \ sides|$  

$C= \dfrac{-c-2}{-3}$  $|Divide \ both \ sides \ by \ -3|$

$C= \dfrac{-c-2}{3}$