Aimme is right. All the sides are obtuse. They do not equal exactly 90 degrees.
If the roots to such a polynomial are 2 and

, then we can write it as

courtesy of the fundamental theorem of algebra. Now expanding yields

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.
So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use

as a root. In this case, that would make our polynomial

so that the answer is (probably) the third choice.
Whoever originally wrote this question should reevaluate their word choice...
Answer:
1st term= 8 2nd term=6 3rd term=4 4th term=2 5th term=0 6th term=-2 7th term=-4 8th term=-6 9th term=-8 10th term=-10
Step-by-step explanation:
hope this helps
Answer:
The 26th term of an arithmetic sequence is:

Hence, option A is true.
Step-by-step explanation:
Given
An arithmetic sequence has a constant difference 'd' and is defined by

substituting a₁ = -33 and d = 4 in the nth term of the sequence



Thus, the nth term of the sequence is:

now substituting n = 26 in the nth term to determine the 26th term of the sequence




Therefore, the 26th term of an arithmetic sequence is:

Hence, option A is true.
Answer:
3/4
Step-by-step explanation: