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sattari [20]
3 years ago
6

Help! These triangles are not drawn to scale. Use the Pythagorean Theorem to determine which is a right triangle.​

Mathematics
1 answer:
podryga [215]3 years ago
3 0

Answer:

A is not. I cannot see B. C is not. I cannot see D either.

Step-by-step explanation:

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Jayden measured a community college and made a scale drawing. He used the scale 22 millimeters : 9 meters. The actual length of
juin [17]

Hey there! :)

Answer:

x = 242 mm.

Step-by-step explanation:

Begin by setting up a proportion between the actual college building and the drawing.

\frac{22mm}{9m} = \frac{x}{99m}

Cross multiply:

99 × 22 = 9 × x

2178 = 9x

Divide both sides by 9:

2178/9 = 9x/9

x = 242 mm.

5 0
3 years ago
Help me
Komok [63]

Answer:

system of equations are

y=53x + 10, y=55x

Step-by-step explanation:

y=mx+b where x is the number of tickets purchased and y is the total cost.

We need to frame the equation for each option

Option 1: $53 for each ticket plus a shipping fee of $10

1 ticket cost = 53

So x tickets cost = 53x

shipping fee = $10 so b= 10

So equation becomes y=53x + 10

Option 2: $55 for each ticket and free shipping

1 ticket cost = 55

So x tickets cost = 55x

shipping fee =0 so b= 0

So equation becomes y=55x

5 0
2 years ago
2. (02.01 LC)<br> 2x - 20<br> Solve:<br> 2x = 20<br> = 2x
Lubov Fominskaja [6]
The answer is x = 10
6 0
3 years ago
the sum of three number is 202, the second is three more than the first number, the third number is three times the second numbe
sertanlavr [38]

Answer:

x = 38

y = 41

z = 123

Step-by-step explanation:

x + y + z = =202

y = x + 3

z = 3y = 3(x + 3) = 3x + 9

<u>x</u> + <u>y</u> + <u>z</u> = <u>x</u> + <u>x + 3</u> + <u>3x + 9</u> = 5x + 12 = 202

5x + 12 = 202

5x = 190

x = 38

y = x + 3 = 41

z = 3y = 123

4 0
3 years ago
Hello pls help I'm dumb thx it's pre calc
Bumek [7]
(f-g)(x)=f(x)-g(x)=
\frac{2x+6}{3x}-\frac{\sqrt{x}-8}{3x}=
\frac{2x+6-(\sqrt{x}-8)}{3x}=
\frac{2x+6-\sqrt{x}+8}{3x}=
\frac{2x-\sqrt{x}+14}{3x}
answer is A
3 0
3 years ago
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