Answer:
Length of string used by Claire = 7 / 3 feet
Step-by-step explanation:
Given:
Length of string Claire in starts = 
feet
Length of string Claire in end = 
feet
Find:
Length of string used by Claire
Computation:
Length of string Claire in starts = feet = 25 / 6 feet
Length of string Claire in end = feet = 11 / 6 feet
Length of string used by Claire = Length of string Claire in starts - Length of string Claire in end
Length of string used by Claire = [25 / 6] - [11 / 6]
BY taking LCM
Length of string used by Claire = [25 - 11] / 6
Length of string used by Claire = 14 / 6
Length of string used by Claire = 7 / 3 feet
$20 a week for 10 weeks is:
20*10 = $200
She spends $6.75 each day for 5 days:
6.75*5 = $33.75.
Lets subtract her spending from her savings to find out how much she has left:
$200-$33.75 = $166.25
Answer:
a) v = 12.21m/s
a = 4.07 m/s²
b)v = 11.24m/s
a = 3.75 m/s²
Step-by-step explanation:
a) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 100
s₀ = x
v = v
t = 9.69 - 3 = 6.69s
s = s₀ + vt
100 = x + v*6.69
100 = x + 6.69v
As x = 3v/2
100 = 3v/2 + 6.69v
100 = 1.5v + 6.69v
100 = 8.19v
v = 12.21m/s
a = v/3 = 4.07 m/s²
b) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 200
s₀ = x
v = v
t = 19.30 - 3 = 16.30s
s = s₀ + vt
200 = x + v*16.3
100 = x + 16.3v
As x = 3v/2
200 = 3v/2 + 16.3v
200 = 1.5v + 16.3v
200 = 17.8v
v = 11.24m/s
a = v/3 = 3.75 m/s²
Sqrt 5 because it’s an imperfect square. Fractions with integers are always rational and sqrt 9 is perfect so it is also an integer.
Numerator = -3( - 8) = - 3 - 8 = -11
Denominator = 5 + 7 = 12
So the quotient = -11/12
Answer
- 11/12
