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3 years ago

Is (-1, -6) the solution to the following system? y = 4x - 2 Y = -2x - 14

Mathematics

1 answer:

Stolb23 [73]3 years ago

6 0

Answer:

the answer to the question are 1 and 2

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Factor each expression completely6x^2+x-2

Citrus2011 [14]

$6x^2+x-2$

first , set the function equal to zero

$6x^2+x-2=0$

now we can use this expression to factor

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

where a is 6, b is 1 and c -2

so, replacing

$\begin{gathered} \frac{-(1)\pm\sqrt[]{1^2-4(6)(-2)}}{2(6)} \\ \\ \frac{-1\pm\sqrt[]{1+48}}{12} \\ \\ \frac{-1\pm\sqrt[]{49}}{12} \\ \\ x=\frac{-1\pm7}{12} \end{gathered}$

x has two values

$x_1=\frac{-1+7}{12}=\frac{1}{2}$ $x_2=\frac{-1-7}{12}=-\frac{2}{3}$

we have the two roots now we chang the sign and make the factor expression

$(x-\frac{1}{2})(x+\frac{2}{3})$

8 0

1 year ago

Need this now<br>need it----------<br>----------

lina2011 [118]

Answer: X = kuv/ (u+v)

that means that x(u+v)/(uv) = k, a constant. so you want x such that,

x(3+3)/(3*3) = 3(3+1)/(3*1)

x=6

8 0

3 years ago

A square table has a perimeter of 20 feet. What is its area?

RSB [31]

Answer:

25 feet squared :)

Step-by-step explanation:

20/4 = 5

5^2 = 25

5 0

2 years ago

PLEASE HELP!!!!! possible widths for a rectangular garden are 5 feet, 6 feet, and 7 feet. Leon wants the area of the garden to b

Nataliya [291]

Answer:

Step-by-step explanation:

3 0

3 years ago

a square dance set requires 4 couples 8 dancers with each couple standing on one side of a square. There are 250 people at a squ

sveta [45]

Given:

1 set requires 4 couples 8 dancers.

Total number of people at a square dance = 250.

To find:

The greatest number of sets possible at the dance.

Solution:

We have,

Total people = 250

1 set = 8 people.

$\text{Number of possible sets}=\dfrac{\text{Total people}}{\text{People required for 1 set}}$

$\text{Number of possible sets}=\dfrac{250}{8}$

$\text{Number of possible sets}=31.25$

Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

$\text{Number of possible sets}\approx 31$

Therefore, the number of possible sets at the dance is 31.

7 0

3 years ago