Simple...
as far as I can see it looks like you need two names for the angle formed..-->>
the angle would be acute
and
complementary
Meaning both those angles <DHR and <DHM have to be both smaller than 90° but when you add them both they should equal 90°.
Thus, your answer.
y = ( 48 *2 ) / 6
Step-by-step explanation:
If y varies directly as x they are directly proportional, which means they relate to each other in the same way....
2 : y = 6: 48
what is y if x = 2?
The value of y can be found if you write it a two fracrions
2 : y = 6 : 48
2 / y = 6 / 48
cross multiply the fractions gives
6*y = 48 *2
divide left and right of the = sign by 6 gives the answer:
y = ( 48 *2 ) / 6
(if you solve it you get y = 12 but that was not the question).
Other method:
multiply left and right of the = sign by y
2 * y/y = y *6 / 48
6y / 48 = 2 * 1
multiply left and right of the = sign by 48
6y * 48/48 = ( 48 *2 )
6y = ( 48 *2 )
divide left and right of the = sign by 6
6/6* y = ( 48 *2 )/6
y = ( 48 *2 ) / 6
(if you solve it you get y = 12 but that was not the question).
Given:
The graph of a downward parabola.
To find:
The domain and range of the graph.
Solution:
Domain is the set of x-values or input values and range is the set of y-values or output values.
The graph represents a downward parabola and domain of a downward parabola is always the set of real numbers because they are defined for all real values of x.
Domain = R
Domain = (-∞,∞)
The maximum point of a downward parabola is the vertex. The range of the downward parabola is always the set of all real number which are less than or equal to the y-coordinate of the vertex.
From the graph it is clear that the vertex of the parabola is at point (5,-4). So, value of function cannot be greater than -4.
Range = All real numbers less than or equal to -4.
Range = (-∞,-4]
Therefore, the domain of the graph is (-∞,∞) and the range of the graph is (-∞,-4].
Answer: b) two sides and the included angle are congruent
<u>Step-by-step explanation:</u>
RS = QS SIDES are congruent
∠PSR ≡ ∠PSQ ANGLES are congruent
PS = PS SIDES are congruent
ΔPSR ≡ ΔPSQ by the Side-Angle-Side (SAS) Congruency Theorem
Since we know the triangles are congruent, we can state that their parts are congruent:
Congruent-Parts of-Congruent-Triangles are-Congruent (CPCTC)
Answer:
No, they are not proportional. 3/5 with equal out to 15/25 by using the method of Least Common Denominator!
Step-by-step explanation:
Hope this helps :)
