Find the inverse of the function y=x^2-12

1 answer:

7 0

Swap the y with the x. So
 $y=x^2-12$
 $x = y^2-12$ 
Now solve for y
 $x = y^2-12$ 
$x + 12 = y^2$
 $\sqrt{x + 12} = \sqrt{y^2}$
$\sqrt{x + 12} = y$
$y = \sqrt{x + 12}$
Inverse notation:
$f(x)^{-1} = \sqrt{x + 12}$

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