Answer is A: when you add all the percents it’s 50 the rest is 50%
Answer:
-8 - 1/3n ≤ - 25
solving-n E [51,+oo] , {n|n ≤ 51}
answer-n ≤ 51
Step-by-step explanation:
I hope its help
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Mandy Increases her books by 2 per month.
Bill increases his books by 4 per month.
Month Mandy Bill
May 18 4
June 20 8
July 22 12
August 24 16
Sept 26 20
Oct 28 24
Nov 30 28
Dec 32 32
At the end of December they will have read the same amount of books.
Answer:
5. LCM of 7 and 14: <u> </u><u> </u><em><u>1</u></em><em><u>4</u></em><em><u>. </u></em>
multiples of 7: <u> </u><u> </u><u>7</u><u>,</u><u> </u><u>1</u><u>4</u><u> </u>
multiples of 14: <u> </u><u>1</u><u>4</u><u> </u>
LCM of 8 and 12: <u> </u><u> </u><em><u>2</u></em><em><u>4</u></em><em><u>. </u></em>
multiples of 8: <u> </u><u> </u><u>8</u><u>,</u><u> </u><u>1</u><u>6</u><u>,</u><u> </u><u>2</u><u>4</u><u> </u>
multiples of 12: <u> </u><u> </u><u>1</u><u>2</u><u>,</u><u> </u><u>2</u><u>4</u><u> </u>
Step-by-step explanation:

Answer:
Population Mean = 2.0
Population Standard deviation = 0.03
Step-by-step explanation:
We are given that the inspector selects simple random samples of 30 finished products and computes the sample mean product weight.
Also, test results over a long period of time show that 5% of the values are over 2.1 pounds and 5% are under 1.9 pounds.
Now, mean of the population is given the average of two extreme boundaries because mean lies exactly in the middle of the distribution.
So, Mean,
=
= 2.0
Therefore, mean for the population of products produced with this process is 2.
Since, we are given that 5% of the values are under 1.9 pounds so we will calculate the z score value corresponding to a probability of 5% i.e.
z = -1.6449 {from z % table}
We know that z formula is given by ;
~ N(0,1)
-1.6449 =
⇒
⇒
0.0608 *
{as sample size is given 30}
⇒
= 0.03 .
Therefore, Standard deviation for the population of products produced with this process is 0.0333.