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bekas [8.4K]
2 years ago
12

Find the midpoint of the line segment with end coordinates of: ( − 2 , − 4 ) and ( 2 , − 10 )

Mathematics
1 answer:
Sholpan [36]2 years ago
5 0

Answer:

(0, - 7 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

here (x₁, y₁ ) = (- 2, - 4 ) and (x₂, y₂ ) = (2, - 10 ) , then

midpoint = ( \frac{-2+2}{2}, \frac{-4-10}{2} ) = ( \frac{0}{2} , \frac{-14}{2} ) = (0, - 7 )

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1/4 + 1/2 + x = -3/4<br><br> WHAT IS X
wel

Answer: step by step

Step-by-step explanation:

fraction form: x= -3/2

decimal form: x= -1.5

subtract 1/4 and 1/2 from both sides to find x

6 0
1 year ago
(27 points for whoever answers this ) Write an expression to represent the sum modeled in the following number line.
FinnZ [79.3K]
-3\dfrac13+\dfrac63=\dfrac{-10+6}3=-\dfrac43
4 0
3 years ago
1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides
salantis [7]

The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.

<h3>What is the significance of "Area under the curve"?</h3>

This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.

<h3>What is the justification for the above answer?</h3>

Area = \int\limits^1_0 {(e^x-x)} \, dx

= \int\limits^1_0 {e^x-x} \, dx - \int\limits^1_0 {(x)} \, dx

= e¹-(1/2-0); or

Area = e -1.5 Squared Unit

The related Graph is attached accordingly.

Learn more about area bounded by curve:
brainly.com/question/27866606
#SPJ1

3 0
2 years ago
What is the answer/explanation for this question
yan [13]
There’s no picture or anything.
8 0
3 years ago
Read 2 more answers
given the functions f(x)=4x^2-1, g(x)=x^2-8x+5, and h(x)=-3x^2-12x +1, rank them from least to greatest based on their axis of s
Lesechka [4]
The formula for axis of symmetry is -b/2a.

For f(x):
0/2(4)
0/8
Axis of symmetry= 0

For g(x)
-(-8)/2(1)
8/2
Axis of symmetry= 4

For h(x)
-(-12)/2(-3)
12/-6
Axis of symmetry= -2

Order from least to greatest: -2, 0, 4

Final answer: h(x), f(x), g(x)
7 0
3 years ago
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