Answer:
The correct option is B. Fermentation would occur at a similar rate to that of glucose.
Explanation:
Fermentation can be described as a process in which alcohol is released by using sugars. In fruit juices, fructose is present mainly to get the sweetness. It is used as a substitute for glucose because fructose is more sweeter than glucose. Both fructose and glucose are monosaccharides with the formula C6H12O6. The only difference is in the arrangement of molecules in the atoms of these compounds. Hence, the rate of fermentation would be same for these two sugars.
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Answer:
It decreases the levels of cAMP in the cell, repressing transcription from the lac operon.
Explanation:
When glucose is absent, cAMP serves as coactivator binds to CRP, the catabolite gene activator protein. The CRP-cAMP complex binds to the site near the lac promoter and stimulates the expression of the operon by RNA polymerase many folds.
Catabolite repression refers to inhibition of the synthesis of enzymes of lactose catabolism when glucose is present as an energy source. In the presence of glucose, synthesis of cAMP is inhibited resulting in its lower cellular concentration. The lower cAMP levels do not allow the binding of cAMP and CRP. The result is reduced expressed of lac operon.
<span>The phase of the cell cycle that is most similar between a cell that will divide by mitosis and one that will divide by meiosis is the S-phase. </span>I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions.
