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3 years ago

Can someone please help with this one

Mathematics

1 answer:

bagirrra123 [75]3 years ago

7 0

Answer:

m∠8 = 123°

Step-by-step explanation:

∠1 and ∠8 are alternate exterior angles, and since lines A and B are parallel, then they must be congruent.

So, m∠1 = m∠8

Substitute: 123 = m∠8

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Step-by-step explanation:

25 - 15 = 10

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2 years ago

Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?

azamat

Answer:

${(x + 6)}^{2} + {(y - 2)}^{2}=10$

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

${(x - a)}^{2} + {(y - b)}^{2} = {r}^{2}$

From the question, the center of the circle is located at (-6,2) and the radius is

$r = \sqrt{10}$

We substitute the center and radius to get:

${(x - - 6)}^{2} + {(y - 2)}^{2} = {( \sqrt{10} })^{2}$

Simplify to obtain:

${(x + 6)}^{2} + {(y - 2)}^{2}=10$

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2 years ago

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Answer:

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3 years ago

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All you are basically doing is making ratios.
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